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13 years ago
-- Indeed, since: q_tot = integral I*dt from 0 to infty should read: q_tot = integral I*dt from 0 to t, I believe. ;) From: http://www.thefreedictionary.com/ampere-second "ampere-second - a unit of electrical charge equal to the amount of charge transferred by a current of 1 ampere in 1 second." So, for one coulomb of charge to be transferred through a one ohm resistor in one second, the voltage would have to remain at one volt for one second. Such is not the case when a one farad capacitor is charged to one volt and connected across a 1 ohm resistor for one second, since the voltage will decay from 1V to 0.368V during that time and there'll be: Q = CV = 1F * 0.368V = 0.368 coulomb still left in the cap when it's disconnected.