Yes, they carry energy and "knocked loose" electrons. But the total charge contained "inside the box" stays _constant_, does it not? No charge was created, was it? Or destroyed?
I agree, Larkin _is_ a pig... Thank You !-) ...Jim Thompson
Yes, they carry energy and "knocked loose" electrons. But the total charge contained "inside the box" stays _constant_, does it not? No charge was created, was it? Or destroyed?
I agree, Larkin _is_ a pig... Thank You !-) ...Jim Thompson
Same thing, different word. It's more common to actually measure in ampere-seconds using resistors, voltmeters, scopes, ammeters, stuff we generally have handy. I do actually own one meter that literally reads coulombs, a Keithley 610C
ftp://jjlarkin.lmi.net/Keithley_1gig.JPG
which is a wonderful old beast to have around. It's shown measuring a
1 Gohm resistor, a feat that has been declared impossible in this very newsgroup.Some scopes will calculate the area under a curve, allowing one to measure charge from a current waveform. Usually you can just eyeball it close enough for lots of apps, or calculate charge indirectly.
Good grief, you *don't* understand this stuff.
You, like AlwaysWrong, are certainly smart enough to learn the basics of electrical circuit math, but for some emotional reason you have chosen not to. I see that a lot in techs. They compensate by attacking people who can do the arithmetic, calling them eggheads or "inexperienced" or argue over definitions and third-order effects to obscure the fact that there *are* calculable answers.
John
Right. "Conservation of charge" in an electronic circuit has to be cited under exactly specified conditions. In some circuits, it makes no sense at all, so it should only be used carefully.
I can extract all the energy from one cap and dump it into another one such that the summed charge of both caps is not conserved.
John
Just to clarify what I assume is a typo there: they carry energy and "knock loose" electrons. That is, they do not carry electrons around with them!
It really does depend what definition of charge you are using. A "differential" charge is created, Q=CV.
The number of electrons and protons in the box stays constant. These are the only charge carrying particles, so the total "physicists" charge has to be constant. This is what is normally meant when we talk of laws of charge conservation.
Yet not many *electronic engineers* would say that the "charge" in the battery/capacitor was zero. It *is* zero, strictly, physically, because the positive charge on the anode is cancelled by the negative charge on the cathode. But this is a useless definition for electronics - its pretty much *always* zero!
The Q=CV "charge" that we talk about, in the electronics engineering context of capacitors, charge pumps and circuits, is not subject to "conservation".
[...]
I see, your a total moron... If you put a flashlight in the box then the system is not isolated as you have opened up the box and added energy(even if the flashlight is not on).
Your simply incompetent and hence the confusion you have. You have a lack of understanding of basic physics. It wouldn't be so bad if you didn't pretend to be god's gift to EE.
For example, you seem to think temperature = energy. Temperature is a form of energy. You seem to think if you have a completely closed off box with X energy in it then that X will turn Y magically. This is because you have no clue what energy is, what an isolated system is, and the concept of logic.
I got A's in college physics. How did you do?
Temperature is a form of energy? Gosh. How many joules are there in
300 Kelvins?John
I like this quote:
Fudd's Law (Fudd's First Law of Opposition)
"If you push something hard enough, it will fall over..."
Essentially, it means "I think we're all Bozos on this bus."
Their brains decayed far faster than that cap after they left school.
Herein lies the flaw with John L's claim, and your flaw if you are following his line of thinking.
It most certainly does. It is not an average.
It is a rate.
If the measure will be shorter than one second, then another unit of measure should be used.
Squirm.
New to physics?
milliampere-seconds? or millisecond-amps?
Like I said. There are better terms to use to describe the same event.
You are obviously not new to being the complete asswipe that you are.
No. It is an integral.
No, no, no! A coulomb is a coulomb. If a capacitor stores a coulomb of charge, and you remove it all, you get a coulomb, one ampere-second, out, and it doesn't matter how long you take to do it, or whether ths discharge is constant, exponential, quarter-sine, or anything else.
You can get one constant ampere for one second. Or get 0.1 amp for 10 seconds. Or a thousand amps for a millisecond, if it's a suitable good cap.
It's like a gallon jug that contains one gallon of water: whether you empty is fast or slow, uniformly or not, you always get a gallon in the end. That's how much is in there!
John
It most certainly does not. Any more than a kWh means one kilowatt of power was consumed over a one hour period. Or achieving a speed of 70mph means you actually travelled 70 miles for a one hour period.
Amp-seconds is a measure of *integrated* charge. Do you always charge your 1200mAH NiMh batteries at 1200mA?
Not it is not. It is *amp-seconds*, not Amps per second!
What, the "2 amp - half second"? Is that going to be a new SI unit?
I'm afraid I've lost track of some of the nyms - but I do believe you must be that AlwaysWrong guy.
If you're so right, how come AlwaysWrong agrees with you? :) :)
AM = AlwaysMistaken.
John
--- Earlier on you seem to have been vaccillating as you so often do when you're waiting for someone to slip and give you an answer you can claim you already knew, so do you now firmly believe that charge isn't conserved?
Final answer, or are you going to dance around some more?
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