As I explained, I've interviewed and hired a number of ex-military folks. And done a goodly amount of military systems design, including stuff that flew or went to sea. And spent a week as a guest of the Navy, which was a lot of fun [1] but convinced me that it wasn't something I'd enjoy doing for years.
John
[1] I didn't have to follow orders, they couldn't court-martial me, and we got to go out on ships and shoot guns off the fantail and stuff like that.
They tended to be rigid and rule-driven. And they tended to respect me too much as "the boss", sort of a superior officer thing I guess. That meant that if I told them to do something that that turned out to be wrong, they'd just keep doing it. That's not what I need.
When I did the formal military electronics, I didn't own the company, so I chust vas following orderss like a good soldier. We have done some lately, like the AH130 heads-up display, but it was "COTS", which means they bought commercial-quality stuff without all the MIL nonsense. Turns out that the COTS stuff is, on average, more reliable than the formal MIL electronics. The system we replaced had a flight MTBF of 22 hours.
Have you ever designed official MIL-spec electronics, using all approved JAN parts and rules and multiple design reviews/qual testing/acceptance testing/source inspection?
Precisely. They follow rules, I make or break rules.
Yep. Now where's your solution to Larkin's Folly #9 ?:-) ...Jim Thompson
-- | James E.Thompson, CTO | mens | | Analog Innovations, Inc. | et | | Analog/Mixed-Signal ASIC's and Discrete Systems | manus | | Phoenix, Arizona 85048 Skype: Contacts Only | | | Voice:(480)460-2350 Fax: Available upon request | Brass Rat | | E-mail Icon at
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| 1962 | Since New Yorkers think it appropriate to boycott Arizona over stopping illegal immigration and drug trafficking, I suggest that everyone else support building the Muslim Monument at Ground Zero
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
Since New Yorkers think it appropriate to boycott Arizona over
stopping illegal immigration and drug trafficking, I suggest that
everyone else support building the Muslim Monument at Ground Zero
Damn it, Jim! I'm an engineer, not a miracle worker.
--
Paul Hovnanian mailto:Paul@Hovnanian.com
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I had a dog that would chase anyone riding a bicycle.
In the end I had to take his bicycle away.
It's _really_ easy once you stare at the waveforms for awhile... I _knew_ charge has to be conserved, but I finally saw the answer while half dozing at a granddaughter's swim party :-) ...Jim Thompson
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
Since New Yorkers think it appropriate to boycott Arizona over
stopping illegal immigration and drug trafficking, I suggest that
everyone else support building the Muslim Monument at Ground Zero
A capacitor in an electronic circuit doesn't store charge, it stores energy. The circuit passes a charge thru a capacitor. For every electron that enters the + end another electron leaves the - end. So the capacitor doesn't store charge with respect to the external circuit any more than a resistor does. Art
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
Friday is Wine and Cheeseburger Day
Said another way - the external circuit uses energy to move charge (electrons) from one plate of the capacitor to the other. No net electrons are added to the capacitor, ergo it has no charge with respect to the rest of the circuit.
Using Larkin's paradox as an example. Charge 2 parallel 2uF caps to 0.5V. Total charge moved from - to + is 2 coulombs, 1 coulomb per cap. Rewire the caps to be in series and discharge. Total charge leaving each cap is 1 coulomb. No electrons were created or destroyed in this process. Art
All that math is admirable, but there's a simpler way to calculate the energy lost in the resistor.
Connect two caps, charged to diffferent voltages, with a resistor. Observe the voltage waveform across the resistor. It starts at some initial voltage Ve = Vc1-Vc2. It decays with some time constant tau = R * Ce, where Ce is the equivalent value of C1 in series with C2.
As far as the resistor can tell, it has just been connected to a capacitor Ce, charged to V, and it discharges that. The waveform across the resistor is identical. So it burns energy equal to 1/2 * Ce
Omigod! A convert! Better go back and study some basics :-( ...Jim Thompson
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
Friday is Wine and Cheeseburger Day
OK. No problem. Where'd the charge come from in your "example"? ...Jim Thompson
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
Friday is Wine and Cheeseburger Day
That's pretty much my model too. So why not enlighten us?
Of course there are usually several ways of describing any physical system that end up amounting to saying the same thing in a different way. I suspect that your epiphany may turn out to be something like that. But we'll never know if you just sit there going "huh?".
To be specific, that current is the displacement current.
Curiously, that current even appears to flow in free space, in the = absence of matter. I don't know if the quantum vacuum has anything to = say about that.
Maxwell's original derivation of displacement current assumed = polarization charge seperation occured in a polarizable medium. That = works for plastic, and it could even work for air, but it's a lot harder = to explain for a vacuum.
Tim
--=20 Deep Friar: a very philosophical monk. Website:
I'm waiting to see if there's someone out there who can solve it.
I should have time to write it up this weekend.
Of course both you and Artemus need to study up on the basics of capacitors. "That's pretty much my model..." is not the _accepted_ condition :-) ...Jim Thompson
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
Friday is Wine and Cheeseburger Day
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