Minimilist Level Shifting

Series diode or two, pull down resistor.

Reply to
Clive Arthur
Loading thread data ...

Or single 1.8V series zener, if your 0V doesn't mind being ~0.7V or so.

Reply to
Clive Arthur

You mean +0.7V, no?

Reply to
Ricky

Yeah, bad habit, I tend to use the tilde to mean approx.

Reply to
Clive Arthur

Sorry. I'm having a poor vision morning and thought it was a -. Tilde I understand.

Thanks for your suggestions.

Reply to
Ricky

What's the zener drop?

What's the zener current?

Where can I buy a 1.8v zener?

Reply to
John Larkin

tirsdag den 11. april 2023 kl. 16.27.42 UTC+2 skrev John Larkin:

formatting link

Reply to
Lasse Langwadt Christensen

I actually did that once. I had a board in production where I had forgotten about the voltage difference. I added a zener in series and let it play against the protection diode. It was a really ugly solution, but could be done without a board spin. Maybe that's why I don't like the series resistor idea. This is all too kludgy for me. Is 200 ohms enough? Is 600 ohms too many?

The logic parts are tiny and easy to buy. 5V tolerant regardless of Vcc. Yeah, that works great for me!

Reply to
Ricky

What will the zener voltage drop be in the proposed circuit?

Reply to
John Larkin

tirsdag den 11. april 2023 kl. 17.01.21 UTC+2 skrev John Larkin:

does it matter? if a simple resistor is somehow not good enough there's no point in not using a 5V tolerant buffer

Reply to
Lasse Langwadt Christensen

Depending on the current some LEDs are in that range. You get a zener and a light to boot.

Reply to
Ralph Mowery

tirsdag den 11. april 2023 kl. 17.38.41 UTC+2 skrev Ralph Mowery:

an LED is missing the diode in the other direction

Reply to
Lasse Langwadt Christensen

If it makes anyone feel better, I did find the spec on the part involved. They allow 10 mA into the protection diodes for a pin and 120 mA total for a bank. But, since they have no app note or any further info in the data sheet, there is no specific exception given to the max Vin on the I/Os, beyond Vcc + 0.3V. There's also the power consumption issue. A resistor of any given value would have a power drain amount that varies 3 to 1 or more.

The two resistor approach has better potential. The ratio of resistors would be something like 3:1, drawing limited current when high, and a low impedance for speed. But even a pair of 0402 parts is as large as the dual inverter.

At this point, I'm good with the dual inverter with specified 5V tolerant I/Os. I'm not interested in exploring the analog properties of a large digital device.

Reply to
Ricky

with the series resistor the current taken from the 5V ends up in the 3.3V so if 3.3V is made with a linear regulator from 5V it is not wasted

Reply to
Lasse Langwadt Christensen

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.