Instantiation of BUFGMUX

Aug 03, 2004 0 Replies

Hello,



I have to instantiate a Xilinx BUFGMUX manually (VHDL), since Precision Synthesis doesn't infer it in this situation. The signal, which is the input for the BUFGMUX, is driven by a clock divider.



The example in

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doesn't work.



How can I make the instantiation, but in such a way, that there is no need for special treatment depending on simulation or synthesis.


Tom


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