how 33-bit BRAM?

Question

HiI need to implement 33-bit data BRAM.Obviously, following BRAM  will not work.Does anyone suggest how to implement 33-bit data, if possible?Thank you in advance.component RAMB16_S36_S36   port (DOA   : out STD_LOGIC_VECTOR (datawidth-1 downto 0);         DOB   : out STD_LOGIC_VECTOR (datawidth-1 downto 0);         DOPA  : out STD_LOGIC_VECTOR (3 downto 0);         DOPB  : out STD_LOGIC_VECTOR (3 downto 0);         ADDRA : in  STD_LOGIC_VECTOR (8 downto 0);         ADDRB : in  STD_LOGIC_VECTOR (8 downto 0);         CLKA  : in  STD_ULOGIC;         CLKB  : in  STD_ULOGIC;         DIA   : in  STD_LOGIC_VECTOR (datawidth-1 downto 0);         DIB   : in  STD_LOGIC_VECTOR (datawidth-1 downto 0);         DIPA  : in  STD_LOGIC_VECTOR (3 downto 0);         DIPB  : in  STD_LOGIC_VECTOR (3 downto 0);         ENA   : in  STD_ULOGIC;         ENB   : in  STD_ULOGIC;         SSRA  : in  STD_ULOGIC;         SSRB  : in  STD_ULOGIC;         WEA   : in  STD_ULOGIC;         WEB   : in  STD_ULOGIC);

John_H · Accepted Answer

Keep the RAMB16_S36_S36 definitions as they started (no datawidth-1, please) out so your primitive doesn't generate errors when it tries to get reconciled with the code.

Instead, just use the 32 data bits and 1 of the 4 parity bits. Ta da!

33-bit memory.

MNiegl · Answer

or you just take any next sized primitive (or 2 in parallel) and padthe rest with zeros.

Ray Andraka · Answer

Depends on how deep you need the memory to be. Size the memory primitives to match your depth requirement, then instance as many as are needed for your data width. If, for example, you need 512 or less words, then a single 512x36 BRAM does the trick. If you need 16K depth, then you need to use 33 1x16K BRAMs.

how 33-bit BRAM?

Join the Discussion

Didn't find your answer?