color code on radial inductors

Oct 25, 2007 6 Replies

Hello, does anyone know exactly how to read the color code on radial through hole inductors? They have two small color dots on top and one or two big dots on sides. I tried to search on the internet but seems like all internet color codes are for well known axial (resistor-like) inductors.



Thanks in advance Francesco



If they are like this

2 large - Gold, Brown 2 small - brown,black placed in that order between gold and black it means 100uH, gold presumably means tolerance or just an identifier but its on the left hand side of reading the dots, unlike resistor bands.

At least on pale blue cased globular ones it is

I will add to my tips files , URL below

-- Diverse Devices, Southampton, England electronic hints and repair briefs , schematics/manuals list on

formatting link

What are the colours on yours ?

-- Diverse Devices, Southampton, England electronic hints and repair briefs , schematics/manuals list on

formatting link

I chose a bad example gold,orange,orange, black means 33 uHenry

gold,brown,green,brown means 150uH

-- Diverse Devices, Southampton, England electronic hints and repair briefs , schematics/manuals list on

formatting link

For physically larger ones (again light blue body) with 3 dots only , read from the top and multiplier nearest a pin. eg brown,black,red = 1000 uH , not 200uH

-- Diverse Devices, Southampton, England electronic hints and repair briefs , schematics/manuals list on

formatting link

yes, pale blue globular. The gold side dot isn't always present. So the lateral dot is the multiplier?

Thanks Francesco

means

the

For the 4 dot ones, the 2 small dots on the top, farthest from the pins, and the large dots on the sides. So presumably a small 3 dot one, with one large dot on its own, is the multiplier.

-- Diverse Devices, Southampton, England electronic hints and repair briefs , schematics/manuals list on

formatting link

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required