Xilinx XC95108 Chip

Look in the data sheet.

The number of FFs should be simple. The number of gates is (much) more complicated.

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The 108 has 108 cells. Each has a FF.

Steve

One cannot load a VHDL program in a chip. What you load is a bitstream, which results from running first synthesis and then several implementation phases. If your design doesn't fit in a particular chip you know it when your implementation fails in one of the phases. When this happens you don't have a bitstream to load. So, I don't understand what and how you were trying to load?...

/Mikhail

Well, I ran all the programs ( running fc2,design manager ... )and implementation and all phases were successful.It's only at the last stage where I have this problem,the chip's memory size is too small to store my vhdl program.

By the way, the XC95108 has 108 cells , what are cells ? so the sc95108 can store 108 flip-flops ?

Thanks for the help.

You really should read the data sheet.

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The numbers in the suffix stand for macrocell count. So, a XC95108 woould have 108 MCs. A MC contains a register, PTA (product term allocator) and a switch matrix. You should read the datasheet for more info. Also a "chip's memory size" does not make any sense. The 9500s do not have any on-chip memory. Maybe you meant that the device is over-utilized?