Let's say I've got a bridge rectifier downstream of a power transformer, and I want to calculate the size of filter capacitor I'll need, allowing for a 5% drop in voltage.
From Vcap = Vo exp( -t/RC ), C = t/R ln(Vo/Vcap)
Let's say that the power supply will need to power an amplifier feeding a 4-ohm speaker, so R=4 ohms.
At 60 Hz, a bridge rectifier will give two |sin x| peaks in 1/60 sec. One peak will occur in 1/120 of a second. The worst case scenario is half of this - the portion from the top of the peak to 0V, which occurs in 1/240 sec.
C = (1/240s) / (4 ohm) ln ( Vo / 0.95 Vo )
C = 53 uF.
Anything larger than this is a waste, then... ?
Thanks,
Michael