Stepped sine wave

My intuition suggested changing only one digital output at a time -- which is why I gravitated towards Gray coding. Searching on that led me to Walsh, which seemed right on the money. But I still haven't had time to read about them. I did just receive my beautiful copy of Harmuth's "Sequency Theory" book, though. And glad to have it. And it does go directly into Gray code ordering of Walsh functions, so I'm happy now.

On the short PDF, I clearly got this message. (odd and even functions, etc.)

Got it.

It's not my application, but George's. He's using a 4017 (decade decoder thing) right now (or was) and ties in resistors on each of the 10 pins to a summing point of an opamp in order to make a stepped sine wave. But he didn't like the spectrum he got, especially the 2nd harmonic.

I hadn't done this, but my gut told me that the 4017 was changing two resistors nearly at once (but perhaps not exactly so) and with ripple carry and all I wasn't comfortable and wanted to suggest thinking in terms of a gray coded approach. Which is what led me to Walsh, which I'd not heard of before but wish I had.

Jon

You mean 154 feet of empty bins?

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The 4017 is a twisted ring shift-register-based Johnson counter - whence no ripple carry within the counter, though it does have a ripple carry output.

The second harmonic content was almost certainly due to the tolerances on his resistors - P-channel on-resistance is higher than N-channel in most CMOS logic, but in modern parts the channel resistance is too low to have explained the second harmonic content he saw.

-- Bill Sloman, Nijmegen

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Thanks, Bill, for the correction on that point.

I was explaining my early reasoning for commenting at all, which as you point out isn't the explanation. I've learned that much as I've been reading here. So that's been good for me. However, I remain very happy to have learned a few things about gray code ordered Walsh functions, too.

Anyway, thanks for the summary and correction. It helps.

Jon

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Hi Bill, did you read the rest of the thread? I measrured an output impedance of ~180 omhs (at 15V) for the 1MC4017 I was using. That's about 2% of the smallest resistor (10k ohm). Bigger than the 1% resistor tolerance, and certianly the major cause of the 2nd harmonic distortion in my first circuit.

George H. (I hope you can forgive the slight correction, I didn't want the thread to end with a mis-statement)

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So here's a late Friday night question, (after a few Genny's). If I used a bipolar output (switching the sign at zero with an opamp, and picking new resistors), would the distortion caused by the output impedance move from the 2nd harmonic to the third? Squishing both sides equally rather than just pushing the top down.

I find it hard moving from distortion in the time demain to the frequency domain.

George H.

On March 30, 2006, Tim Shoppa started a thread in this newsgroup that has some relevance to this. It should be easy to find at Google.

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Forgive it? I'm grateful for it. I knew I should have checked before I posted that comment, but succumbed to the temptation to wing it.

I am a bit surprised that you had an MC4017 to play with. I know that they are still commercially available, but it's difficult to imagine any good reason for using them, unless you are hopelessly addicted to

When I put together a similar circuit in the late 1970's (to make pseudo-random noise to confuse echo-locating bats) I got worried enough about the CD/MC output impedances to use 4066's to do the switching, but I still had to redo the resistors after I found out about Gibb's oscillation the hard way and had to aply a Hamming raised- cosine window to almost every one of 32 carefully trimmed resistances.

-- Bill Sloman, Nijmegen

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If the resulting waveform has inversion symmetry, i.e. if for all t

f(t) + f(t+T/2) = 0,

then it can't have any even harmonics.

Cheers

Phil Hobbs