Looking for a Low Cost On Delay Timer

Based on your limited information, the CD4060 would be a better choice than the 555, but if this is automotive, industrial, or some other less than ideal environment, things get complicated real fast regardless of the parts used:

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. . . . .12VDC >---+-------+----------------------+---+---+---o------v N.O. . | | | | | ------o---> . | +--------. | | | --------- . | | | | | +--|\ \ \ \ \|--. . | | | | | | + --------- - | . | --- | | | | 12VDC | . | --- 0.22u | | | | | . | | X7R | | | |1N4148 | . | --- | | | '--||--+ | | --- | /// . | | | | /// | . --- [10K] | [33K] | . /// | ----------------------- | | . | | VDD | | | . | | | | |/ . +------|RST CD4060 Q14|-+-||-+--| 2N3904 . | | | | 2x 1N4148 | |> . [220K] | ---- | | [10K] | . | |Phi1 Phi0 Phi0 GND| | | | . | ---------+------------- | '----+ . --- | | | | | --- . /// | | | --- | /// . | | | /// | . +-------|------|--|

Reply to
bloggs.fredbloggs.fred
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Hi Fred, a counter solution is nice. Can I ask a silly question? Where the bleep is the oscillator? The R's and C tied to the Phi inputs?

Thanks, George H.

Reply to
George Herold

Classic 3-inverter CMOS RC-oscillator:

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. . . . . . . ____ . Phi1 |\ |\ Phi0 |\ Phi0 . .-| o-----| o---+---| o--+----> . | |/ |/ | |/ | . | [R] | . | | C | . '----[R']-------+---||---' . . .

Reply to
bloggs.fredbloggs.fred

Make that the classic 2-inverter CMOS RC-oscillator:

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. . . . . . . ____ . Phi1 |\ Phi0 |\ Phi0 . .---| o---+---| o--+----> . | |/ | |/ | . [R'] [R] | . | | C | . '---------+---||---' . . .

Reply to
bloggs.fredbloggs.fred

I use this one all the time on my chip designs (without the divider needed for avoiding ESD clipping with discrete devices)...

...Jim Thompson

--
| James E.Thompson                                 |    mens     | 
| Analog Innovations                               |     et      | 
| Analog/Mixed-Signal ASIC's and Discrete Systems  |    manus    | 
| San Tan Valley, AZ 85142   Skype: Contacts Only  |             | 
| Voice:(480)460-2350  Fax: Available upon request |  Brass Rat  | 
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I love to cook with wine.     Sometimes I even put it in the food.
Reply to
Jim Thompson

As in my ancient RCA data book...

...Jim Thompson

--
| James E.Thompson                                 |    mens     | 
| Analog Innovations                               |     et      | 
| Analog/Mixed-Signal ASIC's and Discrete Systems  |    manus    | 
| San Tan Valley, AZ 85142   Skype: Contacts Only  |             | 
| Voice:(480)460-2350  Fax: Available upon request |  Brass Rat  | 
| E-mail Icon at http://www.analog-innovations.com |    1962     | 
              
I love to cook with wine.     Sometimes I even put it in the food.
Reply to
Jim Thompson

There's something about the 2-inverter that tends to hang at small time constant and squegg at large time constant. I think they discovered that after the 4060 was in production.

Reply to
bloggs.fredbloggs.fred

If you're making this with CMOS gate chips, it's a good idea to stick to the unbuffered variety. The usual (these days) buffered gates can ring on the transitions. Somtimes.

Reply to
Spehro Pefhany

Yep. Horrendous crossover currents. On my chips I use unbuffered small inverters...

Reply to
Jim Thompson

Yes that is the way I would do it I have done many many projects using a

555 Time IC..
Reply to
Frank Williams

Simple just use the Reset Pin..

Reply to
Frank Williams

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When 12VDC is applied to the input, I need a 12VDC output for 5 seconds. Then output will go back off and stay off until the input goes to zero. Then cycle starts again.

Current for both legs is in the 10-50ma range.

A simple on-delay timer would work but I'm having trouble finding one with NC contacts. Tons of stuff $100+, but for this application, it has to be under $20.

===

Thanks for all the tips and good info. I had wanted to put something together from components but my brain is too far behind these days. I'm going to give this a shot and hopefully I'm not picking the wrong one. It's $5 at Frys...

Velleman MK111

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Reply to
Guv Bob

On a sunny day (Sun, 25 Aug 2013 23:29:54 -0700) it happened "Guv Bob" wrote in :

The reason I did not reply with a ciruit or whatever is that your logic is false.

You say: 'until', that means the output goes active again. Then you say : 'cycle starts again', but that cycle is not the same now (starts active).

First, for yourself, work out the correct logic. Then you already have the solution, probably from stuff you have laying about.

Reply to
Jan Panteltje

It can be modified to do what you say you want.

Reply to
Spehro Pefhany

seconds. Then output will go back off and stay off until the input goes to zero. Then cycle starts again.

with NC contacts. Tons of stuff $100+, but for this application, it has to be under $20.

together from components but my brain is too far behind these days. I'm going to give this a shot and hopefully I'm not picking the wrong one. It's $5 at Frys...

Hmmmm....... in that case, forget the electronics! ;O)

Reply to
Guv Bob

Thanks Fred, Jim... Sorry my bad. I don't know the 4060.. I didn't realize it had a built in oscillator.

George H.

Reply to
George Herold

seconds. Then output will go back off and stay off until the input goes to zero. Then cycle starts again.

with NC contacts. Tons of stuff $100+, but for this application, it has to be under $20.

together from components but my brain is too far behind these days. I'm going to give this a shot and hopefully I'm not picking the wrong one. It's $5 at Frys...

- Hmmmm....... in that case, forget the electronics! ;O)

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If I disconnect pin 7, would that make it a one-shot pulse?

Reply to
Guv Bob

On a sunny day (Thu, 29 Aug 2013 10:18:17 -0700) it happened "Guv Bob" wrote in :

+12 | -----------------------------------------------------| | | | | | --- | === | / \ 1N4001 Load --- 1000uF / 16V | 1u poly --- D2 | | C2 === C1 |-------------- /// | |--- d -------------| | IRLZ34 | 4M7 | |--- s T1 [ ] R --- | | / \ D1 /// /// --- | 1N4148 ///

When power is off C1 is discharged. When power comes on the gate of MOSFET T1 is posive via C1, and C1 slowly charges via R1, R.C time, select a suitable capacitor and resistor. The gate voltage slowly drops, and then T1 stops conducting. When power goes off, then C1 is discharged again via D1.

D2 and C2 are needed to prevent transients on the drain (load line) of T1 piercing the gate electrode isolation layer.

IRLZ34 is a logic level (2 to 3 V gate on IIRC) MOSFET.

Alternative solution:

12 V light bulb -> wakes up cat -> cat drinks from cup -> cup get lighter -> balance turns -> ball rolls, hits bell -> you wake up, and swtich of the power.
Reply to
Jan Panteltje

Try leaving out R2 & RV1* and D2*, and jumper the free end of R1 (R1-D2 junction) to pin 8.

If you can't quite get 5s with RV2 cranked up all the way, increase R1 to 10K or 20K.

*optionally; if they're already in there, don't bother taking them out.
Reply to
Spehro Pefhany

What discharges that 1000uF (and the 1uF) when the transistor isn't turned on? Or are you assuming push-pull drive on the 12V?

Maybe replace C2 with a resistor and put 1K/12V zener before the cap.

12v heater boils off water so weight on microswitch is reduced. When power is removed relay N.C. contact allows solenoid valve/flow switch to refill water container. Oh, and wire in a beeper to bother the cat.
Reply to
Spehro Pefhany

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