Hey, German in a datasheet! Haven't seen that in a while.
3V is a tall order, almost needs a nuclear fireball as a transmit pulse.This is off the cuff so use with a grain of salt:
What drives the LED? If a uC, maybe you could spare another pin and hook the cathode of the LED to that instead of ground. For receive you could switch the normal drive pin to low, then set this new pin to open drain input with pull-up resistor, hoping the uC has internal pull-ups and allows that. This would save the cost of an extra resistor which you'd have to provide if there is no interal pull-up feature. Now the LED would operate in photoconductive mode and when enough light falls on it the voltage on this nwew pin will be pulled down. Since internal pull-ups are usually in the 50-100k range (or a similar current source) this method would only require sufficient light to generate 50uA of photo current.
They are often sensitive slightly below the wavelength of emitting operation. So in your case possibly something around 600nm.
:-)
If you do that make sure there are no humans or animals close by who could retain eye damage from that.