EM radiation

Just ask a really cool guy named Scotty to " beam " you.

..... Phil

The fields, either magnetic or electrostatic, will vary with the radiation device, such as antenna or coil. Antenna would need an RF power amp in the range you need. I used to have a generic power amplifier used to test ultrasonic up to about 10 Mhz. You feed the power amp with an RF signal generator. Low frequencies are best radiated with a coil.

greg

You need an "RF Generator" or "Service Monitor".

Here are a link I Googled using "IFR" to get you started, though this is not exhaustive by any means... (IFR is a manufacturer, and I've used them before with good results.)

This gear probably does more than you need, and they are expensive. You may be able to lease one. Or, you can try around two-way radio repair shops in your area and try making friends with one of the techs.??

HP, and others, also make stand-alone RF Generators. You will need to know what frequency range you are interested in. You will also need to know how much RF power you wish to generate, and whether or not it exceeds the capabilities of the above.

Then depending on what you intend to do, you may need to design a calibrated "antenna" system so you can control the RF transfer to your device under test. -mpm

I assume you meant radio-frequency. If otherwise, my post above may not be what you want?

That was very helpful- thanks a lot!

Hmm. A signal generator into a loop antenna? of course, you didn't specify how much radiated power you were looking for?

If you really want a wide RF range you might try a spark gap transmitter:

And don't forget the sun as a source! At least IR to gamma.

Chuck

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Actually, the bottom end is much lower than that. It radiates a lot of 0.000125Hz

If my math is right, that's over 2 hours a cycle. So I guess you really can get sunburned with just a quarter- wave.... :)

-mpm

How does it manage that? An antenna even as big as the orbit of Earth is still small compared to that wavelength (of 2.4 billion kilometers). The Sun is positively tiny compared to that wavelength.

Carcinotron.

Electromagnetic radiation can be radio, microwave, infrared, visible light, ultraviolet, soft to hard X-rays, etc.

The 'radio' range is about 200 kHz to 1 gHz - frequency difference

For 'as wide a range as possible' there are synchrotron sources of hard X-rays that can give 10**22 Hz frequency range.

As I understand it: The sun sends out streams of charged particles. This makes it appear much larger than its obvious size and there is a lot of horsepower available to drive the poor radiator.

Absolute frequency yes, but relative, no. Sunlight covers a little over one octave, if that (~400-1000nm). The sun puts out little IR (since its black-body peak is in the visible range), and the atmosphere filters the UV tail.

Tim

-- Deep Fryer: A very philosophical monk. Website @

a spinning magnet radiates

Bye. Jasen

When you say "little IR", what are you comparing it with? Blackbody curves for different temperatures never cross--heating up an object makes it glow more brightly at all wavelengths. Thus the Sun is a much brighter infrared source than any terrestrial object, other than a laser.

Cheers,

Phil Hobbs

Other blackbody radiators, normalized by peak output.

As I recall, they do. The sun emits very little microwave radiation, while the cosmic background temperature gives off copious amounts.

(I suppose it might be possible to place microwave detectors on the sun (nevermind the physical difficulty of diodes operating at 7000K, but that's just an engineering problem), collecting the few picowatts of CBR that pass along, relaying that power back to a cold sink which thereby radiates more microwave radiation. Likewise, the cold sink transforms the visible radiation from the detector into additional microwave radiation.

It's an interesting thought, but I'm sure that, if I ran the numbers, I'd discover that it doesn't come out over unity, which is how it ought to be, after all.)

Infrared perhaps, but not far IR or microwave.

Consider: if this were true, then celestial x-ray and gamma sources would be visible on telescopes (assuming there is a direct line of sight, which for energetic radiation, need not be). Many radio and x-ray sources are only visible due to visible-spectrum matter, as I recall.

Tim

-- Deep Fryer: A very philosophical monk. Website @

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