Hey all. I'm working on a project where I need to divide a 6 Hz signal by 2 to get a 3 Hz signal. However, I have really limited space and don't want to use a 14 pin package just for a single flip flop...I'm looking for suggestions on what the most economical method with respect to size and component count to implement a divide-by-two would be?
Divide by 2, least number of components?
Jan 24, 2010
10 Replies
Use a PIC10F200 in a 6 pin SOT 23 package.
You can get one D-type flip-flop in small 8 pin packages, as small as
0.95 mm x 1.95 mm for ball grids:
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But if you have already a microcontroller on your PCB, it is possible to implement it in software, but it depends on your requirements how fast and accurate it needs to be and if your microcontroller has enough spare time to do it (e.g. in a 1 kHz interrupt, if you can live with 1 ms delay and about 1% jitter of the output signal).
Frank Buss, fb@frank-buss.de
http://www.frank-buss.de, http://www.it4-systems.de
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Those are 8 pin packages and should be small enough for your purpose.
http://focus.ti.com/lit/ds/symlink/sn74auc1g79.pdf
JF
No Q/ output
Try the ...g80
Aarrghhhh!!!
And Vcc is 2.7V max! (AUP is 3.3V supply).
Nial.
Is the input a clean, fast logic level? If not, you'll probably need some signal conditioning before the flipflop.
John
Your point being?
JF
Try Fairchild's TinyLogic series. Something like the NC7SZ74 in a US8 package might work for you.
Mark
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