amperage multiplier

If you use a 1 ohm sense resistor, measured voltage across the resistor equals current. Or, if you need isolation, use a current transformer.

Then, you use a voltage multiplier chip, like an AD633 to get the result as a voltage.

You can change this back to a current if you want by using a simple opamp circuit as follows:

VCC + | +-------+ | | | .-. | | | | | | Your load | '-' | | | | |\| ||-+ +---|-\ ||---||-+ ----------|+/ | | |/| | | | | | | | +-----|-------+ | .-. | | | | | | 1 ohm | '-' | | +-------+ === GND created by Andy´s ASCII-Circuit v1.24.140803 Beta

Use a rail to rail opamp.

Regards, Bob Monsen

Was this AC or DC? Why can't you use transistors. Transformers (not "transformators") transform an AC signal from one amplitude to another amplitude. For example 120vac is transformed into 12vac in your video tape recorder with a transformer. Current multiplication is really current amplification, really. If you want more current, you need to design (or purchase) a larger capacity power supply. If you want a serious answer to your question, please provide more information about what you are trying to do.

Here's a weird circuit I ran across that was designed for use with HV AC supplies like Tesla coils. It looks like a sorta inverse of the familiar voltage multipler circuits that use diodes and caps.

+out o | _V_ ________________|______________ | | | | L L L L | | | | ACin o->|--||--->|--||---->|---||--->|---||---->|--o ACin | | | | L L L L |________|_________|_________| | _V_ | o -out

The "_V_"s and "->|-"s represent diodes (select for appropriate V & I characteristics), the "-||-"s are capacitors, and the Ls are fat iron-cored inductors.

(You hafta kinda squish the diagram vertically to see that the Ls connect between the diodes and caps.)

I have not built this, so let us know how (if) it works, OK?

Mark L. Fergerson