Depends on the horse.
Paul Burke
Depends on the horse.
Paul Burke
2+2 = 5, for greater values of 2 and lesser values of 5
martin
Serious error. All shortcuts have disappeared. Screen. Mind. Both are blank.
... snip ...
No, you are misusing them. It is the length of the non-imaginary bit, whose width now becomes the length, due to the rotation through PI/2. By applying i to my normal 1/2 inch bit I end up with a 6 inch hole cutter.
Grant Edwards wrote in news: snipped-for-privacy@grante.rivatek.com:
Which would be par for the course for the antiquated measurement system still in use here in the US.
In verilog, the bit can have four values: '1' '0' 'x' unknown '?' don't care, so a bit is two bits wide :-) VHDL uses more values, so I think you need 5 bits to represent a bit.
My girlfriend told me it's not the width of your bit that matters, it's what you do with it.
I didn't count it because I didn't care ... but I accept your answer of 5.
According to the TV any bit lasting longer that four hours should be immediately treated by a doctor, so the answer would be 4.
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