Relay replacement: 150 volt coil down to 12 volt coil

I need to replace a broken relay. The form factor is like the P&B R-10 style.

The coil voltage of the original is 150 volts DC.

The R10's I can find are 12, 24, or 48 volts.

Is there some way to either adapt a 12 or 24 volt relay, or maybe some simple circuit to lower the voltage just in this one area of the circuit? Maybe a pwm chip on a little circuit board or something???

I have found that P&B make a 115V DC version, but it's going to be pretty expensive and even that isn't as high as I need.

Suggestions?

Chris

Reply to
kc0atc
Loading thread data ...

Are you sure the coil of the original is getting 150V across it to close? Seems excessive, unless the coil is pulling alot of weight.

Digikey has some 110VDC coil relays. That would solve some of your problem. Then, a power resistor of some kind might be able to do the rest. I'm not sure if the form factor would be identical.

formatting link

--
Regards,
   Robert Monsen

"Your Highness, I have no need of this hypothesis."
     - Pierre Laplace (1749-1827), to Napoleon,
        on why his works on celestial mechanics make no mention of God.
Reply to
Robert Monsen

--- A month or so ago I was looking for a little buck regulator to run off of 120V mains, and I didn't have much luck, so if you find yourself in the same boat, depending on how much current your 150V supply can put out, you may not _have_ the option of using a resistive voltage dropper or a linear regulator and going to a lower voltage coil which requires more current. That is, if the 150 volt relay was running with the coil dissipating one watt, the current in the coil would be:

P 1W I = --- = ------ ~ 6.7mA E 150V

while in a 24V, 1 watt coil it would be 1W/24V ~ 42mA, which would be about six and a half times more current than the 150W relay needed. Even if you could get that current out of the supply, the power the resistor or regulator would have to waste would be:

P = I * (Vsupply - V relay) = 0.042A * (150V - 24V) ~ 5.3W

which is over five times what the relay would be using! It gets better the higher the relay voltage gets, with a 115V 1 watt relay needing about 8.7 mA and the dropper wasting only 300mW.

For a 115V 1 watt coil the value of the resistor would be:

Vsupply - Vrelay 150 - 115 R = ------------------ = ----------- ~ 402 ohms I relay 0.087A

390 ohms and 430 ohms are standard 5% values and either would probably work, (with the 430 wasting less power, but I wouldn't want to go out on a limb unless I had the spec's for the particular relay you want to use in front of me.

-- John Fields

Reply to
John Fields

Yes, it sure is. In fact it may be a little higher than 150VDC. This is a 70's vintage ham radio transmitter (a Tempo One aka Yaesu FT-200) which uses mixed solid state and tubes. Thanks for the link to digikey. I will check it out.

Chris

Reply to
kc0atc

Is there a lower voltage supply in the box for the solid state electronics? If so, you could use the 150V signal (divided down with a voltage divider) to turn on a mosfet, which could then be used to power the coil of the lower voltage relay. This would be a much better solution than trying to drop 150V down to 24V, because the divider could use say 1MEG and 100k, which would give you 14V at the gate with only

20mW required of the 150V supply.
--
Regards,
   Robert Monsen

"Your Highness, I have no need of this hypothesis."
     - Pierre Laplace (1749-1827), to Napoleon,
        on why his works on celestial mechanics make no mention of God.
Reply to
Robert Monsen

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.