The process of quantization doesn't require discrete, countable sets of EM mode functions (although that may well make the mathematics easier). Quantization doesn't necessarily restrict the allowed energies.
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Dr. Paul Kinsler
Blackett Laboratory (Photonics) (ph) +44-20-759-47734 (fax) 47714
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SW7 2AZ, United Kingdom. http://www.qols.ph.ic.ac.uk/~kinsle/
Because the first requirement is to understand the physical concept, not play mathematical games. Maxwell plagiarised the work of Faraday, Gauss and Ampere. Maxwell's aether was a dubious analogy dispelled by Michelson, that's why.
Hi Androcles. I use to like this analogy too. Until I learned a few years ago that in E-M radiation the E and B are in phase! At first I thought there was a mistake... but then discovered that the mistake was mine. (Your link shows correctly the in phase behavior so I realize I'm not telling you anything you don't know.)
Anyway the analogy can lead to false conclusions. (At least for me.)
So now I see that the E field at some time was 'created' by some B field at a previous time.... Which starts to 'weird' me out if think too hard. All of a sudden I picture 'photons' travelling in both directions.
Hi Androcles. I use to like this analogy too. Until I learned a few years ago that in E-M radiation the E and B are in phase! =========================================== Then you should unlearn it immediately. If E and B were in phase both would be zero simultaneously and that violates the first law of thermodynamics, you'd create energy from nothing.
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But anyway, Maxwell's equations never did claim E and B were in phase, what you've "learnt" is a rumour spread by the incompetent. ===========================================
At first I thought there was a mistake... but then discovered that the mistake was mine. (Your link shows correctly the in phase behavior so I realize I'm not telling you anything you don't know.)
Anyway the analogy can lead to false conclusions. (At least for me.)
So now I see that the E field at some time was 'created' by some B field at a previous time.... ============================================ Any spark will start the process. A flame is a chemical reaction whereby the electrons of the atoms are rearranged to build a different molecule. 2H2 + O2 -> 2H2O. ============================================
Which starts to 'weird' me out if think too hard. All of a sudden I picture 'photons' travelling in both directions.
George H.
=========================================== Androcles' third law: For every photon there is an equal and opposite rephoton.
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(It's Newton's third law applied to E-M waves and allows for light to travel in beams -- quite simple, really.)
Of course you'll never see a rephoton without a mirror, it is travelling away from you. Rephotons are the major cause of poorly understood spooky entanglement.
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\'By denying scientific principles, one may maintain any paradox.\' - Galileo
Galilei
\'There is nothing so easy but that it becomes difficult when you do it with
reluctance.\'- Marcus Tullius Cicero
New ideas are old ideas resurrected. - Androcles.
Dear RichD: You are most correct that photons don't reflect (even from the shiniest mirror). All photons get absorbed by the surface and the electron orbits re emit light of the correct wave length. Matter in the 'reflecting' surface doesn't need to KNOW the angle of the mirror face. All of the atoms near the surface act to absorb the "off angle" photons being re emitted such that only those photons which have your stated angle can escape the surface. =97 NoEinstein =97
Hmm, Sorry on my second look your picture of a photon has it wrong you've got the E and B fields 90 degrees out of phase. This is exactly what I would have drawn a few years ago.
Hmm, Sorry on my second look your picture of a photon has it wrong you've got the E and B fields 90 degrees out of phase. ===================================== It's right. Just ask any electrical engineer. =====================================
This is exactly what I would have drawn a few years ago. ===================================== You'd have been right years ago. =====================================
But check out this,
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There is a picture if you scroll down a bit.
George H. ================================================= Wackypedia is written by both incompetent kooks and the wise. Kooks outnumber the wise by at least 100:1, perhaps a 1000:1. Wackypedia has it wrong. See the discussion page, there are a set of tabs labelled "article", "discussion", "edit this page" and "history" at the top. YOU can edit the page, I refuse to have anything to do with it.
Faraday wrote E = -dB/dt. He did not write E = B, he did not write dE/dt = -dB/dt and he did experiment. A CHANGING magnetic field produces an electric field. Ask any generator designer.
The kook diagram you've indicated shows E = B. Use this instead:
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And do not write
- Hide quoted text -- Show quoted text -- Hide quoted text -- Show quoted text -- Hide quoted text -- Show quoted text -- Hide quoted text -- Show quoted text -, it irritates me. Delete it before you post to usenet.
BURT wrote in news:8b79ee65-5af0-44a2-bf00- snipped-for-privacy@2g2000prl.googlegroups.com:
So then, what is the truth? If quantization is 'less correct', then what is 'more correct'. If you're going to tell us we're wrong, then tell us what's right. We're listening.
Hi Androcles, Are you so sure you are correct? Or is there some chance you could learn something new? I don't mind trying to work through the mathematics with you.... But only if you are interested. I know about Faraday's law. But we are talking about someting different here. It is the travleing wave solution of Maxwells equations. I think that in the near field of the source you will find that the E and B fields are out of phase. But the far-field traveling wave is different. I'm not much of a theorist. But looking over the solutions (At the moment I'm looking at Volume 3 (Waves) of the Berkley series on Physics) One can see that the spacial derivative of B is equal to 1/c times the time derivative of E. (and visa versa.) From which (with a little math) one can see that the E and B are in phase. (Oh this is the free space solution.)
Hi Androcles, Are you so sure you are correct? ================================= Yes, quite sure. =================================
Or is there some chance you could learn something new? ================================= I strongly doubt you have any new evidence or data, and I'm not really interested in old crackpot theories. But present it if you do. =================================
I don't mind trying to work through the mathematics with you.... But only if you are interested. ==================================
I've already presented
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which you've snipped. If you think you can fault it you are welcome to try. Just remember that mathematics is about proof based on axioms. ==================================
I know about Faraday's law. ================================== That's nice for you. ==================================
But we are talking about someting different here. ================================= No we are not. We are talking about the transfer of energy through nothing, as when you feel the heat and see a big bright ball in the sky. =================================
It is the travleing wave solution of Maxwells equations. ================================= What travelling wave and what is waving? I've seen no evidence of a travelling wave.
I think ================================= You can stop right there. I'm not interested in what you think, show we what you can prove. =================================
that in the near field of the source you will find that the E and B fields are out of phase. But the far-field traveling wave is different. I'm not much of a theorist. ================================= I'm not interested in your theories. You said above you'd work through the mathematics. I'll allow that, but I'm not going to listen to your theories. ================================= But looking over the solutions (At the moment I'm looking at Volume 3 (Waves) of the Berkley series on Physics) One can see that the spacial derivative of B is equal to 1/c times the time derivative of E. (and visa versa.) From which (with a little math) one can see that the E and B are in phase. (Oh this is the free space solution.) ================================= Phase shift is found in the time derivative. It's E = -dB/dt, and E -dB/dx. Or is there some chance you could learn something old?
Oh, I dunno. Some statements you make are just so far off base, there's too much to correct. You might have well have said that mathematics only applies to adding up the prices of groceries.
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