The upper part is the magnetic aspect; the lower part is the electric aspect.
If a rotating magnet turns another magnet then there is an energy transfer across empty space. One rotation corresponds to one photon. That's the nature of light.
The upper part is the magnetic aspect; the lower part is the electric aspect.
If a rotating magnet turns another magnet then there is an energy transfer across empty space. One rotation corresponds to one photon. That's the nature of light.
Which wave is the particle in the the Electric or the Magnetic wave? This question disproves the photon.
MItch Raemsch
One of the interesting little things is using the Einstien equation E-MC*2 . This defines an EQUIVALENT mass for an energy field. This doesn't meean that a photon necessarily has mass but it does carry energy
-- Bob May
rmay at nethere.com http: slash /nav.to slash bobmay http: slash /bobmay dot astronomy.net
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Refelection comes at every angle and every light energy in the spectrum for white light. This means qunatization of energy coming out of the atom isn't always applicable; for example the rainbow.
Mitch Raemsch
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George H.
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e sA mirror is an example of a metal coating that can handle every frequency of light. Quantization does not apply here either. A rainbow and anything exibiting white light cannot be a phenomenon of quantization of energy in the atom. A laser would be an exception that needs to be taken into account. Evidently quantization has a limited applicability.
Mitch Raemsch
"> I don't read and I don't go to school"
Oh well, as Newton (?) said, =93I can see so far, because I=92m standing on the shoulders of giants. =93
George H.
It's my understanding that quantization applies to the detection of EM radiation when the detection involve changing electron states including modifying chemical bonds. It's my understanding that it doesn't apply when detection is accomplished simply by heating (increase in molecular velocity) not involving ionization. So QM can apply to white light and rainbows if you use your eye, film, or a CCD but not if you use a bolometer or thermometer as the detector.
I could be dead wrong, but I consider photons to only "exist" when and where light exchanges energy with matter at a sub-molecular level. At least that view seems to be sufficient for engineering needs when working with emitters and detectors.
Educate me. How does that view conflict with formal QM theory?
Evidently some atoms can radiate and absorb all visable frequencies such as in the example of a mirror. I am not educated.
Mitch Raemsch
"Photons" show up, that is light detection is appears and discrete events, when light is detected, even with thermal detectors. To observe this experimentally you of course need high enough signal to noise, but it is done. For example, super conducting bolometers can not only detect soft x-ray photons as discrete detection events, but also measure their energy with a resolution of a few percent or better. I remember an interesting talk on this work by a professor of physics or astronomy from the University of Wisconsin at Madison.
Bret Cannon
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If light is a particle which of its waves is this particle in? its magnetic wave or electric wave? No. Einstein questioned his photon in the end. He questioned what he won the Nobel Prize for.
Reflection of a mirror is not quantized and happens over all visual frequencies of light.
Quantization has been disproven. It does have application but it is the lesser truth.
Mitch Raemsch
BURT wrote in news:b72906b1-e886-418b-8f3e- snipped-for-privacy@m7g2000prd.googlegroups.com:
So, please tell us. What is the greater truth?
Brian
--
Yes. Don't think of this as "either-or", think of the photon as the oscillation between magnetic and electric fields. To use a mechanical analogy, you might think of the photon as a rubber ball flying through space. It is springy in the X and Y dimensions, and oscillates between having its energy stored in X-compression/Y-elongation, versus Y-compression/X-elongation.
Now take away the ball.
Best regards,
Bob Masta DAQARTA v5.00 Data AcQuisition And Real-Time Analysis
Quite right, Bob. I sometimes use a "leapfrog" analogy, the electric field creates the magnetic field as the electric collapses and then the magnetic creates the electric field in turn.
Quantization is less imorportant.
Mitch Raemsch
BURT wrote in news:abdfaf69-fc01-40fe-a43e- snipped-for-privacy@z35g2000prh.googlegroups.com:
So which is it? "less important" or "has been disproven"?
One implies it exists and the other that it doesn't.
Brian
-- http://www.skywise711.com - Lasers, Seismology, Astronomy, Skepticism Seismic FAQ: http://www.skywise711.com/SeismicFAQ/SeismicFAQ.html Quake "predictions": http://www.skywise711.com/quakes/EQDB/index.html Sed quis custodiet ipsos Custodes?
The truth is meant to be known. Quantization is the lesser concept than full ranges of energy.
Mitch Raemsch
You miss the point: I can quantize the field in any set of basis modes I happen to prefer. However, some basis sets will provide simpler descriptions of the behavior than others. And for some situations, no description will be simple, and I'll have to settle for least-complicated instad.
The process of "Quantizing the field" isn't unique. It's a choice. Generally, though, there is only a small set of useful bases for which quantization gives a useful description.
-- ---------------------------------+--------------------------------- Dr. Paul Kinsler Blackett Laboratory (Photonics) (ph) +44-20-759-47734 (fax) 47714 Imperial College London, Dr.Paul.Kinsler@physics.org SW7 2AZ, United Kingdom. http://www.qols.ph.ic.ac.uk/~kinsle/
Why not consider the Yee grid for discretizing and numerically solving Maxwell's equations? That might be leapfroggy enough for you, without requiring any dubious analogies.
-- ---------------------------------+--------------------------------- Dr. Paul Kinsler Blackett Laboratory (Photonics) (ph) +44-20-759-47734 (fax) 47714 Imperial College London, Dr.Paul.Kinsler@physics.org SW7 2AZ, United Kingdom. http://www.qols.ph.ic.ac.uk/~kinsle/
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