zener!

Oct 15, 2021 Last reply: 4 years ago 23 Replies

The HMC659 output is rated 9 volts abs max. ADI says to take this very seriously, but they would. So I have a 1 pF schottky clamp diode (even that 1 pF is annoying) and then the biased-up bypassed 8.7v zener. It might have to dump 50 mA.

I'd test the amp chip for actual breakdown, but we only have one in stock now and they cost $330 each.

This is nominally an RF part, so it's likely it will really swing to at least 2x Vcc. That's something the RF boys tend to do, specify max supply voltage and not max device voltage. I'll eventually try it and maybe delete the clamp.

I want all the swing I can get, but we only need to bias it high and pulse it in the down direction.

JAN is a military screened/qualified part. No wonder a fighter costs hundreds of millions each.

Microchip must have bought a business with a warehouse bin full of them - and digikey just auto-transfered their stock list.

Aren't robots fun ?

Welcome. Let me take your hat.

RL

Did a little re-engineering, and see that the apparent power and size requirements of your zener look do-able while retaining the majority of the Codatron(R) specifications (on and off datasheet).

Biggie: noise. Guarantee no avalanche type noise or oscillation from zero current to 500uA thru the Codatron(R) module.

That current gets "amplified" by your choice of the current pass transistor which adds its Vbe to the total zener voltage. The module is connected from the base of your NPN current pass transistor to its collector; zener use from emitter to collector.

Size of the Codatron(R) module? Perhaps SOT363. Size of your NPN current pass transistor? Up to you.

Thanks, R. Baer

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