Why? I use switchers on the raw (or slightly filtered) input supply, then a cap multiplier per rail for the sensitive stuff.
Cap multipliers have a nonzero output impedance, so dumping switching spikes into their outputs is, *ahem*, suboptimal.
Cheers
Phil Hobbs
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
I've seen opamps as current sources oscillate with out any series output resistors, maybe try 50 to 100 ohms. Especially if they drive a capacitive load like wire.
I haven't looked at the schematic. I was thinking the capacitive multiplier was another circuit like the charge pump to up the voltage. I looked it up and it's a way to use an opamp to boost a capacitance. But in that case you need higher rails to run the opamp. So why not use a simpler dropping circuit?
Hopefully this is a more detailed description of my circuit since I can't post it. Mind you, after reading what you guys have said, yes there are some questionable design going on with the supplies and c-multipliers.
So I have a +5V_RAW coming into the board. That +5V_RAW then goes to a c-multiplier to make my +5V (for simplicity here, I'm just calling it +5V, but I know it's lower). That +5V then goes to a inverting charge pump to generate the -5V. And that's that.
In hindsight, it should have gone: +5V_RAW to inverting charge pump and then both -/5V go to their own c-multiplier and then I have cleaner supplies for my opamps.
I've never made a C-multiplier with an opamp... always just a bipolar transistor. It does drop ~0.6V and has an output impedance of something like the resistor/ beta (current gain). To me the circuit is more about reducing the effect of the resistance in the LP rather than increasing the capacitance.. so the name in unfortunate in that regard.
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
DC is a moving target, for sure. ;) Motorboating is an AC-coupled amp issue, though, whereas this is a TIA.
Cheers
Phil Hobbs
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
Yup. Op amps aren't much use in high performance cap multipliers, because their supply rejection is inadequate.
Cheers
Phil Hobbs
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
Well, I'll agree that resistive divider is not a good name either. (For a year or so it's refereed to as a Hobbs filter in one of my notebooks, I'm not sure that name will pass the ANSI. :^) (or whomever is in charge of naming things.)
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
cap multiplier is this: --+-------+ +----- | \ 7| [R1] \ / | ----- | | +----------+ | | [R2] === C1 | | ----+----------+-------- the load transient response is approcimately as-if C1 was multiplied by transisor's beta thus capacitance multiplier. the source transient reposonce has time constant R1||R2 times C1, so bigger is better.
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