Theorem derived from the postulates, no matter how trivial.
I am reminded of a Feynman story. In his university days, he would sometimes tease the math students. Feynmen felt that all mathematical theorems were obvious and intuitive from the prepositions, without having to work through the proof itself.
So one day, he challenged a student to present any theorem, and he would decide on the spot if it were true or false. The student chose,
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a classic case of unintuitive results. The student explained the prepositions in terms a lowly physicist would understand: you take an orange, and cut it up into finitely many very small, very complex pieces, rearrange them, put them back together and you get two oranges. "Aha!" Feynman said, for oranges are *not* infinitely divisible -- they are made of atoms, not infinitely divisible spheres. So the student failed to explain the theorem with an appropriate analogy.
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Tim
Deep Friar: a very philosophical monk.
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R
Robert Baer
One must accept certain criteria to be able to prove that 1+1=2; in a general mathematical sense, it does not - in fact, neither number (or digit) may even exist!
R
Robert Baer
You forgot that it also brought us.......MicroSoft!
K
krw
Um, isn't that the definition of '+'? ...or I suppose '2', if you want to go that way.
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Frank Buss
This depends on the axioms. But then you could prove 2+2=4, which needs
25,933 steps, if you are really pedantic:
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Frank Buss, http://www.frank-buss.de
piano and more: http://www.youtube.com/user/frankbuss
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whit3rd
Well, no, the conditions ARE important. The function 1/x, between X=3D1 and X=3D-1 doesn't fit the condition (and the local slope doesn't ever match the 'mean' slope in that range). Between X=3D1 and X=3D2, though, the function IS defined at all points, smooth and continuous, and the theorem correctly predicts a behavior of the derivative.
J
John Devereux
But the theorem does not apply to 1/x *at all* - it only applies to functions which have the same value at two points, between those two points.
John Devereux
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Dirk Bruere at NeoPax
You mean that seeing something that is totally obvious is not a "proof" until written down?
That may well be true. After all, pencil and paper really are not essential to doing maths. Some people can do it in their heads.
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Dirk
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Dirk Bruere at NeoPax
And, of course, smooth and continuous.
Dirk
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T
TheGlimmerMan
Well, if they perfect VDMs and their functionality through real hardware hooks, who care?
T
TheGlimmerMan
Are you trying to read between the lines or write or append between the lines? :-)
D
Dirk Bruere at NeoPax
I'm just surprised nobody mentioned the typo
Dirk
http://www.transcendence.me.uk/ - Transcendence UK
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ehsjr
You were just on such a great roll(e) with your rant that nobody wanted to interrupt it with "x marks the spot" or similar. :-)
Ed
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Dirk Bruere at NeoPax
But would the theorem still work if it was done in pictures instead of Roman/Greek letters? Answer that if you're so smart!
Dirk
http://www.transcendence.me.uk/ - Transcendence UK
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M
Michael Robinson
Well, no, the conditions ARE important. The function 1/x, between X=1 and X=-1 doesn't fit the condition (and the local slope doesn't ever match the 'mean' slope in that range). Between X=1 and X=2, though, the function IS defined at all points, smooth and continuous, and the theorem correctly predicts a behavior of the derivative.
-------Are you saying 1/x is defined at all points between -1 and 1?
M
Michael Robinson
Trolle's Theorem: people will rant about the most ridiculous things.
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Dirk Bruere at NeoPax
Yes, but this is more intellectual than most. It would be wasted in most NGs
Dirk
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J
Jim Thompson
I thought those were fly specks ;-) ...Jim Thompson
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Phil Hobbs
Russell & Whitehead's "Principia Mathematica" goes through more than 500 very dense pages before getting to the point of proving that 1+1=2.
So it's obviously very plausible, but isn't certain till it's proven. Rolle's theorem is part of the scaffolding for the theory of continuous functions (and therefore of calculus), so it's pretty important. There have been some pretty counterintuitive theorems proven in that field, e.g. Fourier's theorem!
Cheers
Phil Hobbs
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Nobody
The problem with intuition is that it doesn't get you very far once you move away from familiar territory (integers, reals) and, worse, can lead you astray. E.g. applying the rules of real arithmetic to complex numbers, assuming Euclidean geometry, etc.
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