Done it many times, as an industrially important process: drive it with a voltage and phase lock on current. Or for a general resistance source (rather than ideal voltage source), you'll assume drive voltage (internal clock) and measure the pin voltage to infer current. Under the restriction Rds(on) < sqrt(L/C), but not by too much, so that the signal is not too small, nor the Q too low.
This will likely restrict what range of L, C can be used, since you get Q
- VCC volts on them and Rds(on) ~ 50 ohms for average HC scale CMOS. And I(pin) < 10mA or whatever, and probably quite a bit below that if it's a low power application.
Maybe not as bad if it's a low voltage CMOS process where you can get low resistance cheaply, but then you need another supply (but hey... maybe make it variable and add AGC?). Or maybe it's reasonable to build a low impedance analog output pin, so the amplitude is small (optionally variable), and low impedance.
You could also do what every crystal ever does: add a loading cap, so your circuit effectively spans a capacitive divider that's part of the resonant capacitor. Crystals having the unique distinction of extremely large inductance and extremely small capacitance (the motional equivalent components), so that the impedance is still rather high (~kohms); a low impedance resonator would need a respectively large loading cap.
If you need a "discrete"* style oscillator (a few transistors and resistors rather than an entire loop), it should be fruitful to look at the V-I transform of a traditional parallel resonant circuit.
*Funny way to put it, since it's going inside a chip...
Tim
Seven Transistor Labs
Electrical Engineering Consultation
Website: http://seventransistorlabs.com
"Jim Thompson" wrote
in message news:hiq8ga91b24hlsji1oh7rnbv7bm0nct23t@4ax.com...
> Oscillator Proposal...
>
> Suppose I have a series RLC, one end grounded, the other end driven by
> a chip, how might I make that into an oscillator?
>
> All wild ideas accepted... this is for a custom chip.
>
> ...Jim Thompson
> --
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