I am looking for an output amplifier for a signal generator

Nope, not so simple Ban. Small offsets in the input pair can easily create say 10% current imbalance, and the resulting 1mA drive will be magnified by the output transistor's beta, possibly leading to >100mA of class-A rail-rail current. If each side's feedback was returned from one of its output transistor's emitters, before the equalizing resistor, the class-A current problem could be mitigated. But what you really want is a way to predetermine and control the quiescent bias current, which ideally for a high-speed amp should not be zero. This can be done by adding current sources and resistors at the input.

.. ---+---+-----------+----+----- .. | | | | .. 10mA 5mA | | .. | | _ |/ |/ .. | +------U-------| fzt2222a .. | | | bead |> |>

.. 1mA | | | | .. | ,---)---)----+------+ | quiescent .. | |/ | \\| | | | Iq = 10mA .. +--| | |--' | | .. | |> | | 1W 1W .. +--| | |--, | | .. | |\\ | /| | | | .. | '-)-----)----+------+ | .. 1mA | | | | .. | | | _ |< |< .. | +------U-------| fzt2907a .. | | bead |\\ |\\ .. 10mA 5mA | | .. | | | | .. ---+-----+-----------+----+----

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 Thanks,
    - Win
Reply to
Winfield Hill
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Maybe the subtlety is the feedback connection between O/P and bases of the long tailed pairs? The current into the output transistors will regulate by itself. We do never saturate or starve the first stage, it's a buffer, not an amplifier. Whatever current is not used in the first stage will flow into the output transistors, it is not controlled by a fixed bias voltage. The right current source has 10mA, half of the left one. These 10mA are consumed by the input transistor, so there is nothing left for the power stage.

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ciao Ban
Bordighera, Italy
Reply to
Ban

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