From the previous page: "VO =3D VCC x fIN x C1 x R1 x K Where K is the =
gain constant=97typically 1.0."
So 15V * 67Hz * .01e-6F * 100,000ohms =3D 1.005V
That is pretty close to 67 Hz per volt.
From the previous page: "VO =3D VCC x fIN x C1 x R1 x K Where K is the =
gain constant=97typically 1.0."
So 15V * 67Hz * .01e-6F * 100,000ohms =3D 1.005V
That is pretty close to 67 Hz per volt.
Would someone take a quick look at the data sheet here please
I've never used an LM2907, but was reading the above a couple of days ago (in connection with the thread '12v relay on 3v ??' in seb).
The +Vout figure of 67 Hz/V for the 'Minimum Component Tachometer' circuit shown at the top of page 8 seems wrong to me. Using the formula given on page 7, I make it 670 Hz/V. That would also be a lot more practical, at least for a car engine!
I'm curious to know whether it's the datasheet or me that's wrong.
-- Terry Pinnell Hobbyist, West Sussex, UK
Thanks, plainly my slip. Maybe I used 10k instead of 100k for R1. (I see manufacturer failed to include component designations, although should be obvious here.)
Also, assuming this was meant to be a typical car tachometer circuit, I thought 67 Hz seemed too low by about a factor of 10, reinforcing my mistake!
-- Terry, West Sussex, UK
I didn't consider whether or not it is a good design. My first problem is an automotive design that has a regulated 15 volt supply and bills itself as a minimum compont count design.
But if we assume that this represents a tach for an 8 cylinder car and the pickup is the distributor pickup (that turns half as fast as the crank shaft does, then 5000 RPM would produce a frequency of
5000/60/2*8=333 Hz for a voltage aoutput at that speed of about 5 volts. That isn't so bad. If you designed it for 670 Hz per volt, the output would be about a half volt/ full scale.
Thanks. My calculation was badly flawed!
-- Terry Pinnell Hobbyist, West Sussex, UK
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