D82C55AC-2

I've bought 10 pcs of "82C55" through mail, and received D82C55AC-2.

The problem is that the output high voltage of any pin is not 5V, but

3.8V.

Nothing is connected to the port pins, VCC is 4.85V.

Am I wrong thinking that CMOS chips should have far more than 3.8V on output pins?

Thanks

Reply to
aleksa
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google a data sheet. will be there.

Cheers Don...

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Don McKenzie

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Reply to
Don McKenzie

Output can never be greater than VCC.

Reply to
linnix

The I/O pins can be in between state after a reset. The Intel datasheet says this happens if the capacitance on the pin is more than

20 pf, but I have seen this happen with chips that had little capacitive loading on the I/O. The I/O pin has a sort of latch function to hold the previous state of the output pin when the output is in "tri-state" mode, which it is after the reset. But after a reset the latch function is in the linear range and can get stuck in an in-between state.
Reply to
Alan Steinhauer

- snipped-for-privacy@w5g2000prd.googlegroups.com...

ys this happens if the capacitance on the pin is more than

oading on the I/O. The I/O pin has a sort of latch

n "tri-state" mode, which it is after the reset. But after

in-between state.

The intel pdf on 82C55 says that the Output High Voltage is minimum 3.0V with 2.5mA load, and VCC-0.4V with 100uA load.

Since there is nothing connected to the pins, it should be minimum 4.85-0.4 =3D 4.45V, not 3.8V.

If I try the D71055C, the output pin is exactly VCC.

(both D82C55AC and D71055C are from NEC)

The chip is initialized after the reset, all ports are in output mode, and all ports are written with 0FFh.

P.S. It is close to 2am, I'm going to bed

Reply to
aleksa

Yes, unless they're listed as "TTL Compatible", which the D82C55AC-2 is.

Hope This Helps! Rich

Reply to
Rich Grise

How much power supply current is it drawing? ;-)

Hint: It's not all that hard to re-mark old ICs.

Best regards, Spehro Pefhany

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Reply to
Spehro Pefhany

Sounds like you got 3.3 V parts when you thought you ordered 5 V parts.

Reply to
JosephKK

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