Im confused. I was operating on a KOSS DVD player and found a defective +5V supply. Just before the +5v output pin, there was a diode (unknown exact type) I measured the voltage at the supply side of the Diode and it read +5V and on the "output" pin side that was NOT connected to anything I read +22V. How the heck is that? At any rate, I removed the diode from the circuit, and now I have the
+5V back. All is not perfect however, the DVD player shuts off every hour or so now. My questions are 1) what do you think that diode was for. 2) why is it possible that I got a higher (much) voltage on the other side of the diode when it was not connected to anything.thanks!