DC Wave Questions

On Sun, 19 Jun 2005 10:37:29 -0500, John Fields Gave us:

Grow the f*ck up, retard.

Note that you STILL likely don't know the meaning of the word cited.

I rest my case. The misogynistic idiot just got trivial... again. Oh... that's right, he never was anything BUT trivial.

On Sun, 19 Jun 2005 10:50:43 -0700, John Larkin Gave us:

And to think that it all started, because the John misogynistic idiot tried to play spell checker... again.

I did post on topic in this thread, btw...

It could just replace the missing words with an equal number of underscores so you can fill in the blanks. ;-)

On Sun, 19 Jun 2005 13:08:52 -0500, John Fields Gave us:

You could be a bit more retarded, but I do not see how.

Not a common word, but there is "misandrist".

Best regards, Spehro Pefhany

Actually, he was being a bit clever, but you choose to criticize anyway, just because it's him posting, I have to assume.

Tom

On Sun, 19 Jun 2005 15:10:43 -0500, John Fields Gave us:

What "myso" error? You are wrong again, asswipe.

BTW...I did mean for that to be choose (present tense), not chose (past tense). :-)

Tom

On Sun, 19 Jun 2005 15:10:43 -0500, John Fields Gave us:

You are an idiot. You jump on others for spelling like a wussified little school marm, yet you choose to not spell several of your written "words". You are a true idiot, and I caught you. That is about all there is to it.

Unfamiliar with everyday colloquialisms now as well? I am not surprised.

Wrong again, asswipe. F*ck off and die now, little boy. You are proof that numerical age does not a man make.

The only components which can be represented by a single parameter L or C are ideal components, which will always have exactly that value. They can't saturate, because their value is mathematically constant. Though you probably can't buy them at digi-key ;-) Compents that you can buy cannot be represented by a single constant parameter, though you may be able to approximate them as such for a useful range of operation.

Not sure about this, but can the air-core inductor you just descrived saturate? Or is it primarily a funtion of a core material like iron or ferrite saturating?

What you did here wasn't evaporating gold at room temperature. By creating a vacuum discharge you sputtered the gold off the surface (by ion impact), and it was this sputtered gold that covered the inside of the jar.

robert

What matters is the Cd partial pressure at the surface. Since the Cd partial pressure in air in normal conditions is likely to be a lot lower than 10e-8 torr, Cd will always outgas at the same rate -- no matter what the surrounding air pressure is.

Of course if you seal a piece of Cd in a small glass container, the surrounding volume will slowly saturate with Cd vapor, and when it is saturated the outgassing will stop (or, more accurately, it will be exactly compensated by re-condensation).

Partial vapor pressure, yes.

No.

robert

I generally watch threads; when I see two names alternate on a really deep one, I know I can just scroll down, shift-rightclick, "mark as read".

When someone new chimes in, I usually check to see what they have to say, and if maybe something interesting came up in the piss contest; same if somebody I respect chimes in - that usually means that the thread has taken an interesting enough turn for me to bother to read the posts.

And when three of the posts by the new guy are nothing but what I see here, I just very quietly click "Articles - Plonk Author".

It makes the thread-checking a little less tedious. ;-)

Cheers! Rich

I remember learning this very thing at a bench in USAF electronics tech school. We did the numbers on paper, and then hooked up a real circuit and all of the phases were off from what we were expecting from the numbers because we had neglected the inductor's own resistance. Once we put that back into our equations, of course, it all came out right. :-)

Cheers! Rich

"... A third, classical definition of saturation is that total magnetic saturation occurs when all of the magnetic domains are aligned and the permeability relative to that of air becomes one. For pipeline steels, ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ this occurs at very high field levels (above 1000 Oersted) and is impractical for flux leakage in-line inspection applications...."

From

So, I'm guessing, No and Yes. ;-)

Cheers! Rich