Help with understanding this circuit

Jul 29, 2003 2 Replies

Lets say you have 2 capacitors of equal capacitance wired in series and this combination wired in series with a resistor, R1. Now, obviously you can find the equivalent capacitance of the 2 caps and the circuit becomes a standard RC deal.



But suppose that you place a load between the 2 capacitors. Say a resistor, R2. Basically, how do you model this circuit?



If the load were an LED, and the values correctly chosen, would it light at all?



Thanks


this

resistor,

From what perspective? If you want to model it just as a series RC (i.e., what is the equivalent RC seen across the end nodes), it's the series combination of all these elements - the total resistance is R1 + R2, and the total capacitance is

1/2 C (where C is the value of each of the two equal caps), and that's that.

at

Initially, sure - but if connected to a DC supply, the LED will turn off just as soon as the capacitors are sufficiently charged.

Bob M.

In article , snipped-for-privacy@rogers.com mentioned...

You haven't given enough information to answer the question. Like which two points is the LED connected? Draw a ssimple diagram for us using courier font. If the voltage is less than about 2 volts, the LED will never light, no matter where you connect it.

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