I'm looking for a non-complex way to convert a 5MHZ signal to a dc level with little if any ripple. The signal is at 5MHz with amplitude of 0-5 volts. When the signal is present a + 2.5 to +5 Vdc output is required. When the 5MHz signal disappears a 0 volt output is required.
Are you basically looking for a frequency to voltage converter??
LM2917 or LM2907 depending on the application, I don't know what its maximum frequency capability is, but you can check out the specs at National Semiconductor.
Hope that helps.
-- Myron Samila Toronto, ON Canada Samila Racing http://204.101.251.229/myronx19
cut what follows into a text file called Detector.asc and open it using LTSpice: You can then play around with optimising the turn on time (determined primarily by the ratio of C2/C1), the turn off time (determined primarily by the C1R2 time constant) and the amount of ripple while it is on. My solution uses a series dc blocking capacitor so that you dont have to know which state (high or low) your RF source is in when no 5Mhz is present.
it sounds to me all you need is an RF switch. a nice little germanium diode as the detector into a small cap, this signal can drive a common emitter amp as the inverter that drives another inverter , the output of this can drive a current Boost stage(Unity gain).. that is just off the top of my head , there are more details that has to be worked out like the resistors etc.. if you don't get any where with this let me know i can most likely pop up a schematic of something that will work ok.
Like I said over in sci.electronics.design, the guy isn't clear what he wants. Take a bunch of people, and they will interpret his vague post multiple ways.
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