Bonjour =C3=A0 tous,
j'ai dans ma netlist :
- gnetlist -g spice-sdb -o exo_freqence-periode.net exo_freqence-periode.sch
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- Spice file generated by gnetlist *
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*=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D Begin SPICE netlist of main de= sign =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D VBF 0 n0 DC 0 PULSE(1 -3 2NS 2NS 2NS 10NS 100NS) .INCLUDE ./simulation.cmd R2 0 n1 1k=20=20 R1 n1 n0 1k=20=20 .end
Pas de quoi fouetter un chat donc. Avec ngspice, je fais :
******
** ngspice-20 : Circuit level simulation program
** The U. C. Berkeley CAD Group
** Copyright 1985-1994, Regents of the University of California.
** Please submit bug-reports to: snipped-for-privacy@lists.sourceforge.net
** Creation Date: Fri Nov 20 10:19:22 GMT 2009
******
Circuit: * gnetlist -g spice-sdb -o exo_freqence-periode.net exo_freqence-p= eriode.sch
ngspice 1 -> run Doing analysis at TEMP =3D 27.000000 and TNOM =3D 27.000000
No. of Data Rows : 1
Initial Transient Solution
--------------------------
Node Voltage
---- ------- n0 -1 n1 -0.5 vbf#branch -0.0005
No. of Data Rows : 3044
ngspice 2 -> plot n0 ngspice 3 ->=20
Et l=C3=A0 je ne comprends pas car la base du signal se situe =C3=A0 -1V et= le pic =C3=A0 3V...? Bref, c'est comme si j'avais branch=C3=A9 la sonde de l'oscil= loscope =C3=A0 l'envers ! Il doit y avoir une inversion dans les nets...