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Two part circuit

Hi

I am beginer in electronics. I would like to make the following circuit

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but I am confused with some parts in it. It is not clear to me how is VCC_OUT iteracting with the other part of the circuit. I supose it is connecting somehow to VCC at pin 10 and/or VCC at R4. But, it is really not clear to me how this should look in practise. Could someone please explain a little bit?

I ask this question also in another group, but I think it is best for here.

Thanks, Goran

Reply to
eden
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Thanks for the reply, Petrus.

Can you explain me which VCC is which? I mean, the one that emits and the one that consumes the power. I supposed that power comes from VCC_OUT, right? And from there it connects to pin 10? Or to VCC near R4?

I suppose I seem like a dumb, but I really don't understand how should I connect these points.

Thanks again, Goran

Reply to
eden

VCC_OUT from IC2 pin 1 should be connected to IC3 pin 10 *and * R4. Given there's little current (in the order of 10s of mA for an ATMega), you can connect it almost any way you want. For best results, keep the wire from IC2 to IC3 short, and let the wire to R4 be whatever length it needs.

Cheers

PeteS

Reply to
PeteS

Pin 10 of IC3, and R4, both need to be connected to a 5V source (VCC). To do that, connect them to Pin 1 of IC2 (VCC_OUT), which is the output of the

5V regulator. Not shown in the schematic, but required, is a power supply providing a voltage in the range of 7 to 30 volts, which IC2 will use develop the 5V.

Don

Reply to
Don Bowey

Thanks a lot to all.

I think that I start to figure out how it should be. I couldn't get it without your help.

I hope I will not mess up.

Thanks, Goran

Reply to
eden

--- VCC_OUT is the source (the one that emits) and both of the VCCs are sinks (the ones that consume). The diagram is drawn badly, and all three locations should have the same label, indicating that they're all connected together. The positive side of the input power supply is connected to "+" , the negative side to "GND", and all of the GNDs are connected together.

---

--- I think you sound pretty smart for asking for help, and the drawing certainly can be confusing.

-- John Fields Professional Circuit Designer

Reply to
John Fields

"eden" schreef in bericht news: snipped-for-privacy@g43g2000cwa.googlegroups.com...

Goran,

VCC_OUT has to be connected to VCC. Guess the one that draw it wants to make a difference between to connection that provides the 5V power and the other connection that consume the power. It's not the usual way of drawing however and apparently leads to some confusion.

petrus bitbyter

Reply to
petrus bitbyter

Near, comp.arch.embedded.

As for now, I think I realised how it should be, with the help of all of you.

Thanks

Reply to
eden

that's because the circuit's a little confused.

good guess, I also think that's what the designer intended. connect VCC_OUT directly to all points labeled VCC on the schematic. (or put a switch in-between etc..)

comp.sys.embedded? yeah, it probably is better asked here.

Bye. Jasen

Reply to
Jasen Betts

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