Re: International standards

Jul 11, 2005 Last reply: 3 years ago 509 Replies

wrote : "Roger Gt" wrote : >An "Under water fan" is normally referred to as a "Wheel" on a : >boat. : : Nope, wheels aren't going to help. He's going to need to put a : propeller on it. : : "Does anal-retentive have a hyphen?" 8*) :

I see you do not speak English, I intended to provide English speaking adults with information, so it was clearly not directed to B. S. (Little Billy Smith)!

In answer to Mr. Smiths inane question, the answer is obvious by inspection, something you are clearly are unaware of, but should be able to see once it is pointed out to you!

BTW, The horizontal wench used to control the rudder is a "Helm" not a wheel. A Propeller is a component, and when installed it is a "Wheel!"

If we are to speak, let us be understood clearly and unambiguously!

Trying to be funny works only if you ARE funny! Otherwise your just a SA!

Take the power and apply it to an underwater fan.

-- Regards ........... Rheilly Phoull

Have a look at the datasheet, there is a graph with the title "Collector-emitter Saturation Voltage vs. Forward Current". From this graph you should be able to see what Vce(sat) will be for various LED forward currents at 25 degrees C. Don't forget to leave some room for variations in Vce(sat) with temperature.

----------------------------------------------------------------------- To reply to me directly: Replace privacy.net with: totalise DOT co DOT uk and replace me with gareth.harris

Ah, now I understand Roger. (Should I bother with the smileys? Naw, Roger Git doesn't git them...)

William Smith ComputerSmiths Consulting, Inc. www.compusmiths.com

Sorry for my ignorance, when I said "just starting to saturate" I meant "just starting to conduct", high voltage drop across transistor low collector current etc.

What I actually need is for the output of the optocoupler to be TTL compatible, because it is to feed other TTL logic circuits in a CNC application I'm working on. This part is for the parallel port breakout board so I don't fry my laptop if I get a short from the 36V 9A motor supply.

The circuit so far is described as this.

Parallel port output > Tri-State buffer / line driver > Opto-Coupler > Drive Logic with separate and independent Vcc and GND either side of the Optocoupler. I could use another buffer on this side of the opto I suppose.

The tri-state buffer is needed for power up and down stability, so the CNC machine can't move during a reboot, the software I'm using outputs a 12.5kHz signal on a parallel port output pin when ready to send data to the CNC machine and I'm feeding that into a 1mS timed charge pump to the Tri-state enable lines, also because my laptop has 3.3V and 5V output voltages from the parallel port, so I thought I'd standardise at 5V. so the breakout board could be used on desktop PC's as well, without overdriving the opto LED's.

25 years ago I was an Army Radio Telecommunications Technician, it's surprising how much you forget if you don't use it.

There are optocouplers available with logic gate outputs which may be easier to use, for example:

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I have found that desktop PCs also have 3.3V parallel port outputs, well mine does anyway I haven't carried out a detailed survey.

----------------------------------------------------------------------- To reply to me directly: Replace privacy.net with: totalise DOT co DOT uk and replace me with gareth.harris

Not a bad idea, but they're bloody expensive, I can get all 3 of my octal chips for less than 4 of these and I'd need 8 of them for all my outputs.

Drive

suppose.

CNC

12.5kHz

Tri-state

from

The IBM PC parallel port spec. says TTL 5V or TTL 0V toggle on output ports, I think the 3.3V comes from using TTL compatible CMOS devices that were not around when the original interface spec. was made up.

I suppose I could use pullup resistors, but that always seems a bodge job to me, think I'll stick to the tri-state buffer with schmitt trigger input for safety > optocoupler > schmitt trigger buffer. That way is a bit belt and braces but should work nicely, I'll let you know.

wrote : "Roger Gt" wrote : >Trying to be funny works only if you ARE funny! : : Ah, now I understand Roger. (Should I bother with the smileys? Naw, : Roger Git doesn't git them...)

No, you Don't get it! Besides, your smiley sucked!

I've got an old modem card here. I'd like to know what the various components do. Have you come across a site that identifies the electronic componets and their functions.



Thanks



SP.



PS. explanations for other boards/cards would also be welcome



X-No-Archive: Yes



The typical variable voltage power supply consist of a voltage control IC and multiple high power transisors such as 2N3055.



The problem with this design is that it's highly inefficient and requires large power supply for the input.



I'd like a design that can use a 12A ish 24V switch mode power supply for input and output stage made of PWM voltage controller much like CPU voltage controller that can drive external MOSFETs.



Is there such thing as one chip controller that will drive MOSFETs and change output voltage from potentiometer input?



Hi,I have a problem with this circuit

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, I try first to calculate and after to measure in a simulation the value of Rin, but the two results are much different!



Where is the mistake?


Data:



Vi= 100mV;



Ii( AC current at the transistor's base ) = 794nA;



hfe = 83.6;



re = 42 Ohm;



Ri ( calculate ) = (hfe+1)*( re + RE ) = 84.6*1042 = 88153.2 Ohm;



Ri ( measured ) = Vi/Ii = 100m/794n = 125944.6 Ohm;



The difference between the two result is too much!



Help me to understand where is my error!



Thanks !



Francesco



To reply in private remove NOSPAM.

Could someone suggest a simple circuit that would light an led for about 2-4 seconds when power is applied and then turn off and stay off until power is cut and applied again?



Thanks in advance JJ __________________________________________________________________


Figure about 15 watts per pound for conventional transformers, maybe

30 or so for torroids. That assumes all the windings are properly loaded, and resistive loads.

John

Have a look at My most up-to-date website Electronics for Beginners & Intermediate Electronics http://homepage.ntlworld.com/g.knott/index22.htm

2-4

is

That's not a bad idea! I'll have to think about that... I still have quite a few technical books, though by no means every tech book I used to.

Based on the diagram, I'm assuming R5 is intended to be the output load. For an emitter follower, it's on the wrong transistor terminal. It should be on emitter for an emitter follower - note this would change the RE value to R3 || R5 ( '||' = parallel reduction ). Strictly, as drawn, C2/R5 do nothing right now - for small signal they are not even part of the circuit since all DC sources are effectively grounded for analysis.

Perhaps you are measuing the correctly wired circuit rather than the displayed circuit diagram: the change in RE is ~0.1% but 0.1% * (Hfe+1) is 8.4% difference in the formula. Not enough to explain the whole difference (formula deviates 29% from measured).

More likely: remember that the Ri/Zi formula you are using is only valid for "small signal".

Try measuring with an even lower input signal level, e.g. 1 mV or 100 uV. 0.1 V is probably not "small signal" enough. Roughly speaking with an 0.1V input and hfe of 83.6, your collector current is going to move significantly so your Q-point/bias point is not going to be where you thought it was.

For a 100 mV DC level you've shifted the Q-point, while for 100 mV AC level you're seeing an integral input impedance of all the traversed Q-points. Considering that, the difference of 88K vs 125K seems like a reasonable result.

Another source of error: is the Hfe measured or from the datasheet? If the latter, there is statistical variance between any actual transistior and what the data sheet says (which is only the average value of Hfe). If measured, how? In reality Hfe = Hfe(Ic) so it's Q-point dependent also. Again gets back to not being small signal. BTW the datasheet value of Hfe is always Hfe(Icmax) where Icmax is the Ic that gives maximum(Hfe) - obvious marketing prefers listing *that* value.

A remote possibility is Rb: the "full form" is Zin(CE/CC|s.s.) = (rb + RB) + (Hfe+1)*(re + RE). Usually Rb is ignorable but not always.

Small signal can be a tricky concept: small signal is small only in the sense of bias point shifting (as in Taylor expansions and the resulting shift of y (or in this case Ic) ), but *not ever* in the human intuition of when signal level seems "small" sense. Thus small-signal really means "*small enough* that I *feel* comfortable ignoring the *actual deviations* from my *assumption* of linear operation". It's an important subtlety.

MM

Namely, look for "one shot" or monostable 555 circuits.

Jon

Try this:

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John

I have a Kenmore electric dryer that went on the blink this weekend. I set the timer (which I can hear running) and push the START button. I hear a humming sound whilst pushing the button but nothing happens. I took the back off and wiggled the wires. Still doesn't work. I couldn't see the belt very good from the back but it looked attached. I can move the drum one way manually.



I have limited tools (my trusty swiss army knife is alls I have used thus far if this gives you an idea). Should I just bite the dust and call a repair person, or are there a few things I can still check.



Thanks in advance.



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