Ppppfffftttttt..... I was *always* right on this point of course !
Graham
Ppppfffftttttt..... I was *always* right on this point of course !
Graham
possible
-- Since when is "a few tens of microseconds or so" instantaneous?
Eeyore a écrit :
Obviously (hem) not.
V = a sin(wt) V'= a w cos(wt) V''=-a w^2 sin(wt) w=sqrt(-V''/V)
a= V''/sqrt(-V''/V)
-- Thanks, Fred.
message
need
i.e.
possible
output
The measurement is instantaneous but it takes a few us to calculate the result.
Graham
You've come up with a smarter method still ?
I'm intruiged. I need to think about that.
Graham
Emitter resistor provides dynamic biasing (holds the current down as the transistor heats and tries to pull more) . The emitter resistor also would hold the signal down (degenerative feedback) without an AC bypass for signal.
----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==----
----= East and West-Coast Server Farms - Total Privacy via Encryption =----
I don't check my work very carefully for newsgroup postings, since the penalty for being wrong is zero. I'm a lot more careful when it matters, which is how I get to sell rev A of most of my boards.
John
As regards being wrong, I and one of my design engineers are working on the architecture of a new product. We visited the customer last week and got an idea of his problems, and we promised him a proposal by this coming Friday. Accordingly, we have allocated Monday, Tuesday, and Wednesday specifically to being confused and wrong as much as we possibly can, and we're doing mighty fine so far. I've been learning stuff about NCOs that I never suspected, and discovered that you can buy a might fine 16-bit DAC for $3 nowadays and that Xilinx has some ultracool logic blocks for free.
Sometimes it pays to be wrong.
John
-- Yup, if you learn from your misteaks. Yes, I know...
Damnation, you're right. I was assuming the frequency was known.
Bob M.
No, he's not right. Well, if we consider that's a sine wave.
Here's what I replied to Graham:
But: a^2 = V^2 + (V'/w)^2
Then: a=sqrt(V^2 - V'^2 * V/V'')
-- Thanks, Fred.
John Larkin wrote in news: snipped-for-privacy@4ax.com:
It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not, It will, It will not,
Nanner nanner boo bo.
-- Posted via a free Usenet account from http://www.teranews.com
"WAZ" wrote in news:1156269157.387710.12830 @p79g2000cwp.googlegroups.com:
No, that is RMS or Root Mean Square.
To calculate peak, mult RMS by 2 x (Square root of 2) (approx 1.414)
Then to get paek-to-peak, multiply peak by 2
-- Posted via a free Usenet account from http://www.teranews.com
-- No. Peak = RMS * sqrt(2)
ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.