MOSFET as a switch and Rds(on)

Jul 15, 2009 3 Replies

Hello,



I'm having a slight confusion over what Rds(on) means for a MOSFET. In the book it says that Rds(on) is the resistance (Vds / Ids) in the linear (triode) region. After the FET enters saturation, the resistance obviously changes as the current stays the same for increasing voltage.



However, people I ask say that they only use FETs for switching (i.e. either cutoff or saturation), and for them Rds(on) is the resistance in saturation.



Which is right? Can you point to a lucid explanation of this topic? Thanks in advance


There are two common uses of the word "saturation" with respect to mosfets. Some people (the more academic types) use it to refer to the higher-voltage constant-current region. Some (more likely to be working engineers) sometimes use it to refer to the low-voltage ohmic region, like the bipolar transistor saturation region. That may explain the confusion.

Rds_on is the slope of Vd/Id for small excursions near zero volts, with some specified amount of gate turn-on voltage applied. It's less ambiguous to refer to this region as the "ohmic" region, and the higher-voltage part of the drain curve as the "constant-current" region.

John

There's nothing wrong with your understanding. "Saturation" has two different meanings, depending on whether you're dealing with bipolars or mosfets.

The Rds(on) when seen in a one line description of the part or on the first page of a data sheet - is "how low" in resistance "it can go" (like bragging) while saturated.

Then they give you curves to modify that figure based on temperature Vds/Ids, etc. with more realistic expectations.

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