A friend of mine dug up this schematic he wants to build with his son.
If you scroll down a bit, you'll see an annotated schematic. It shows the +9V battery and on the right side it has Positive side of B1 and on the left side it has Negative.
I'm not much of an electronics whiz, but that only makes sense to me if the - side of the battery is connected to chassis ground. If you connect the - side of the battery to the voltage divider consisting of the pot and the photocell Q would never trigger.
Am I totally out in left field?