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Small PLD for interrupt flag register

Hi guys.

Just wondering whether someone could suggest a small PLD which would be able to fit my design for a 16-bit wide interrupt flag register. I'm hoping for a DIP package, but I suppose PLCC will do. Not keen on hand soldering surface mount.

The design consists of 16 input pins going into the J inputs of 16 JK flip flops. K inputs are unused. The 16 Q outputs go to a 16-1 mux whose single output goes to an output pin. The 16 CLR inputs go to a

1-16 demux whose enable input goes to an input pin. The select lines of the mux & demux are connected and brought to 4 input pins. Finally the 16 input pins also go to a 16 input OR gate whose output goes to an output pin.
Reply to
chinsta00
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Too many output blocks for a small pld but your design is easily splittable so you could get it into two 22v10 dips.

Reply to
cbarn24050

For small task a XC9536XL comes handy, is in circuit reprogrammable and below 1 Euro. Why stil bother with PLDs?

--
Uwe Bonnes                bon@elektron.ikp.physik.tu-darmstadt.de

Institut fuer Kernphysik  Schlossgartenstrasse 9  64289 Darmstadt
--------- Tel. 06151 162516 -------- Fax. 06151 164321 ----------
Reply to
Uwe Bonnes

Any small CPLD will probably do. Download either Xilinx's WebPack or Altera's Quartus II web edition and implement your design. You can do it with schematic capture exactly from your description. It will then tell you what CPLD will fit the design (probably the smallest possible thing, like an XC9536 or EPM3064).

PLCC pins are wider, but I'd rather put down a TQFP which keeps the pins where I can see them. If you bridge a TQFP pin, it's easy to fix with solder wick. If you bridge a PLCC pin it can be a huge pain in the ass.

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Ben Jackson AD7GD

http://www.ben.com/
Reply to
Ben Jackson

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