power dissipation of the datasheet of an igbt, and real power dissipation

The second part has a larger die, and hence a lower junction-case thermal resistance, but it's a 1200V part (whereas you can get by fine with a 600V part), so it has poorer C-E saturation voltage, e.g., 2.5V vs 1.83V at 60A for the first part. And you could do even better with a large-die 600V part.

Dunno about the calculator, e.g., it's not obvious how they can calculate switching losses without knowing gate-drive current and without specific IGBT knowledge, etc., and their default package case-sink insulator thermal resistance appears too optimistic. I'd want bench verification before relying on the calculator.

Winfield Hill ha escrito:

Thanks for your answer, sorry about my description of my calculator i only give the info about my inverter not about the calculator, in the calculator of course you got to put the thermal resistence, the voltage drop of the diode, the r on of the igbt and the r on of the diode, the t rise, t fall and some more parametres.

I said the second part because is the discrete igbt that i have seen with the biggest power dissipation. I prefer use a 600V igbt, that it adapts better to my specifications of voltage and current and i get lower power losses. can you tell a 600V igbt wich can dissipate my power losses?, thanks so much.

not to appear to be overbearing, but I will soon be selling 300A, 600v half bridge IGBTs for 15 dollars apiece. They are very large and can dissipate a lot of heat, pretty good deal for the price and your little 30a current.

A large IGBT module, good choice. Two appealing features of these modules are the integral heat-sink insulation, and the captive-nut high-current wiring. What's your p/n?

One unappealing feature of IGBT modules is their high price, but this is ameliorated by their availability on eBay from sellers who remove them from old 3-phase motor drives, etc.