I have three DC-5Khz, 0-5 V positive going signals. I'd like to select and pass the highest of the signals, without diode losses. Using a microproces sor is out of the question. Cost is a object and actives should be limited to devices that can be second sourced.
This is for converting a RGB command signal to an intensity signal.
Three opamps, each with a diode in its output. Each acts like a follower, but all three get their nfb from the output node. Needs a pulldown from output to ground or V-, too.
Classic process control "high select."
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John Larkin Highland Technology, Inc
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nd pass the highest of the signals, without diode losses. Using a micropro cessor is out of the question. Cost is a object and actives should be limi ted to devices that can be second sourced.
Yup. A less precise option is putting each input thru a diode, with the out put of the diodes going thru an opamp with a diode in the nfb path to add a diode drop to the output. An extra resistor to supply rail needed to keep the diode biased. 4 diodes 1 opamp versus 3 diodes 3 opamps. The performanc e difference between this and the above should be fairly obvious.
Just add another input to this circuit I posted last November...
bitrexCircuitChallenge_2013_11_07.pdf
on the S.E.D/Schematics Page of my website.
Probably best if you used a quad-OpAmp... three for inputs, the resistor to ground (or to negative rail) to ensure "Who's on first"
Fourth OpAmp as the buffer. ...Jim Thompson
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| James E.Thompson | mens |
| Analog Innovations | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| San Tan Valley, AZ 85142 Skype: skypeanalog | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
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I love to cook with wine. Sometimes I even put it in the food.
With something like this tacked on it will work better at 5kHz:
formatting link
It will still be a bit glitchy where the levels cross.
Best regards, Spehro Pefhany
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"it's the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
The reverse diodes + 10K resistors keep the op-amps from railing. Some op-amps take a long time to recover from being railed (as I think you have measured).
Using Schottky diodes as you suggest would reduce the volts they have to slew.
Best regards, Spehro Pefhany
--
"it's the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
Works okay provided BE junction of Q2 doesn't break down, should be fine for 5 or 6V with just about any transistor.
I guess you could flip Q2 for more voltage- might even reduce the offset.
Best regards, Spehro Pefhany
--
"it's the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
You mean use Q2 inverted? Wouldn't r(e) have the same i*r drop?
Using a compound (Szilaki?) for Q2 would reduce the gain error, but it gets messy. Using the usual feedback resistors you could tweak Q5's gain slightly over unity. (Hey, it's only video, right?)
You can also use transistors instead of diodes, and wire-OR their emitters. That usually makes the op amps better behaved IME. A catch diode (as Spehro shows) helps with the transient.
Cheers
Phil Hobbs
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Dr Philip C D Hobbs
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On a sunny day (Mon, 8 Sep 2014 13:16:11 -0700 (PDT)) it happened " snipped-for-privacy@SpamSucks.net" wrote in :
1) If you are talking about analog video, then the bandwidth would be to 5 MHz, no 5 kHz.
2) The method you describe asks for trouble, as in your black and white picture areas of different color will show up the same, making many things 'unreadable'.
3) The normal way to convert from RGB to BW is a resistor matrix, no 'opamps' needed.
In the European system the ratio for white is .3 R + .59 G + .11 B
You can nicely appoximate this like this:
R -- 3k9 -- |-------- BW G -- 1k8 --| | B -- 10k --
Note that for R, B, G = 1V the output is also 1V.
The rest is, as they say, bullshit.
Your question sucks, so this is a wild guess of what you were trying to accomplish, or not accomplish.
So be more clear in your questions! That saves people time and irritation. Or google first.
If you need super-fast, and no OpAmp-style hangs, study the techniques in Patent 3,643,110 Sample and Hold Circuit, PDF on the Home Page of my website.
All you need is the first half of the schematic.
How it works is detailed in the Patent. ...Jim Thompson
--
| James E.Thompson | mens |
| Analog Innovations | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| San Tan Valley, AZ 85142 Skype: skypeanalog | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |
I love to cook with wine. Sometimes I even put it in the food.
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