matching impedance

While your answer is correct, Jim, it may over-complicate the problem. Most lasers operate at currents of at least 40mA, and as a result have very low intrinsic dynamic impedances. Taking this as an assumption, I matched my wideband 50-ohm RF signal to a Hitachi laser diode with a small 47-ohm SMD series resistor, and added a Picosecond Pulse Labs bias-T to inject the dc current. My network analyzer and TDR tests showed a reasonable 50-ohm termination was obtained. Overall light throughput response was flat, dropping by 1dB at 1200MHz. It should be noted I took special care to maintain effective double-terminated 50-ohm transmission lines for both the laser and PIN-diode receiver. It's possible the latter was responsible for the 1.2GHz rolloff. I noted with amusement that Hitachi's datasheet curves showed a peak at 600MHz, and dropped off rapidly thereafter. I surmised this was the response of their optical detector, or due to bad laser wiring.

Hint 1: All my open-wiring distances were kept to under 1mm. Hint 2: Learn about making high-performance bias-T networks. Pazzeo can read the recent discussion here, and photo postings on a.b.s.e.

Ahem. Pazzeo can "do the math" by replacing my 50-ohm resistor with a 75-ohm part. :>) But as to whether he can make good transmission lines and evaluate them, that may be another matter.

--
 Thanks,
    - Win
Reply to
Winfield Hill
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Hi all, i have this problem: in my circuit i must insert a laser. The problem is that i do matching impedance at 75 ohm. This matching is on a wide band: 80- 900 Mhz. How do i realize this?

Thanks Pazzeo

Reply to
Pazzeo

These are a start, but may be poor substitutes for the technology in the Picosecond Pulse Labs bias-Tee units. We made a PCB version of my lashup, using the MiniCircuits parts, and only got 600MHz performance.

--
 Thanks,
    - Win
Reply to
Winfield Hill

On Sat, 19 Feb 2005 10:28:27 GMT, "Pazzeo" wroth:

First you must measure the laser's impedance for the AC signal over the range of frequencies of interest. Make sure that the DC operating point, if any, is set to the final value during the measurements.

Hopefully, the AC signal will be a small percentage of the DC bias. If it isn't, then the load will be non-linear and matching will be "problematical" at best.

Once you have the measurements, convert them into an equivalent lumped circuit configuration of L, R, and C elements. At that point, if the matching circuit isn't obvious to you, post the circuit here and someone will do the math for you.

Jim

Reply to
James Meyer

formatting link

Reply to
Fred Bloggs

Hi all, I thank all for your help. But I don't resolve my problem. I would send my circuit but it 's very big file. My email is true, if you want you can contact me so I can send you by email my circuit.

Thank for your help Pazzeo "W>>

Reply to
Pazzeo

for Winfield Hill

I search discussion but I don't find anything, can you help me? What is it a.b.s.e.? If you can, you contact me so I send you my circuit, my email is true. I thank you very very much Bye Pazzeo

Reply to
Pazzeo

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