I am designing a circuit. It consists of two parts, the output of the first part is an LED signal, which is ON/OFF based on certain conditions. I require a DC motor to be powered on when the LED is in ON state. Could you please suggest a suitable circuit for the same?
You can get to the pin of the IC? Battery voltage? Is there a current limiting resistor on the led? Does the IC pull to ground (battery minus?) to light the led or does it go high? Will the motor work from a separate power source? How much current will the motor draw (and what kind of motor - little toy motor or earth mover?)
Yes, I can get to the pin of the IC and the voltage is as per the requirements of the smoke detector chip, would be around 9V. I am in the phase of designing the circuit. The motor works from a separate source. I should drive a blower, and hence is a big one.
A good solution would be to add an optoisolator in series with the existing LED. You might have to modify the existing dropping resistor due to the increased v drop of two devices.
The output of the optoisolator can be used to drive a small load, or a large one via a relay.
One thing to consider: The existing LED might be used for more functions than just the alarm output. My smoke detector's LED flashed briefly every few seconds. It also flashes for a low battery condition. You may need some logic on the opto's output to condition the signal.
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Paul Hovnanian mailto:Paul@Hovnanian.com
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