I=92ve been tasked with adding over-voltage input protection to an existing instrument amp circuit (AD620) The Inamp looks at a signal from a parallel tuned LC circuit. R of about 10 ohms and Q ~100, so a source impedance of ~100k ohm (R*Q^2). There is 5 Meg ohm to ground on each input line to the Inamp for bias current.
I was going to use the C-B junction of a transistor (2n3094) from the inputs to power rails, as suggested by Analog Devices. (Apparently this will have less leakage current than a 1N4148.) They suggest a maximum current for the 2N3904 C-B junction of 20mA. Any idea where this number comes from?
I=92m protecting against ~60 volts of overvoltage and so will use a 3k ohm series resistor.
Thanks, George H