Guess This Graph

Dec 31, 2012 8 Replies

It's time for another round of:



Guess This Graph!



See the following datasheet:

formatting link
(apparently they don't have shorter links; part is IDH04G65C5XKSA1) Bottom right page 6, forward characteristics (surge).



The region below 3V is clearly the stuff magnified to the left, but what the hell is the linear region about (>3.8V @ 175C, >5.4V @ -55C)?



Tim


Deep Friar: a very philosophical monk. Website: http://seventransistorlabs.com

How about

formatting link
:-)

M0WYM www.radiowymsey.org Sales @ radiowymsey http://stores.ebay.co.uk/Sales-At-Radio-Wymsey/

That is weird!

It's almost as if the device is behaving as a combination of a "perfect" diode, and a somewhat-temperature-sensitive resistance... but the "resistance" is somehow bypassed, or reduced in value at higher voltages and currents. I can't tell if the higher-slope part of the curve at the left is exponential or just higher-slope linear.

Perhaps there's some sort of second-order effect kicking in, to create a higher-conductivity channel at higher voltages or currents? Something analogous to avalanche in a transistor or a "hot carrier" effect, or an effect of the heating of the junction during a surge?

Dave Platt AE6EO Friends of Jade Warrior home page: http://www.radagast.org/jade-warrior I do _not_ wish to receive unsolicited commercial email, and I will boycott any company which has the gall to send me such ads!

formatting link

Interesting characteristic. The divergence above about 32.5A is interesting, too.

Needless to say, the Infineon Spice model doesn't reflect this behavior.

I guess I shall have to buy one and CT it.

"For a successful technology, reality must take precedence over public relations, for nature cannot be fooled." (Richard Feynman)

formatting link

Am guessing that is the resistivity of the bulk (doped) silicon.

Like maybe it would flatten out at higher voltages and currents, if you had, I suppose, a cryogenic curve?

Maybe? But avalanche is an electric field thing, even with the thinner junction in forward bias it should take quite a bit? And if the voltage drop is due to the resistive bulk, very little additional voltage will appear on the junction itself...

Heating could do it -- t_p = 200us is awfully long, and up at, say, 25A *

5V = 125W, with a 200us single pulse, you get about 1 K/W RthJC and thus 125K temp rise at the end of the pulse, assuming it was held at that level during the pulse. But why that would make it saturate is just... bizarre!

And with such a long pulse, when to they measure it? Do they sample at the beginning, just after series inductances have stabilized? Do they measure at the end? Do they average the whole pulse? Is their source resistive, constant current, constant voltage?

Maybe the excess heat is also activating defects and dopants? This seems to show a similar effect:

formatting link
Maybe a little kink around 3V (p.2 Fig1, top left), not nearly as pronounced.

Tim

Deep Friar: a very philosophical monk. Website: http://seventransistorlabs.com

formatting link

Looks like it would make quite a nice varicap diode. 1v to 10v rev bias gives a nice change in capacitance from about 140pF to 60pF.

That's nothing new -- big power schottkies will do 30nF at zero bias down to a few nF at rated voltage. They tend to stink as varactors though. That said, SiC may have lower dielectric loss!

Tim

Deep Friar: a very philosophical monk. Website: http://seventransistorlabs.com

Infineon replied!

Apparently, it's due to P-N junctions kicking in, perhaps guard ring stuff or something like that. Suffice it to say, an SiC schottky isn't a crystal with a layer of metal glued to it, they do more work to them than that.

They also gave me a reference: Heinze/Neumeister/Rupp: Surge Current Ruggedness of Silicon Carbide Schottky- and Merged-PiN-Schottky Diodes, ISPSD 2008

So if you're still curious, and have access to IEEE,

formatting link
?arnumber=4538944&contentType=Conference+Publications you can get some more answers.

Tim

formatting link

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required