It can be achieved easily if you connect a resistor to the power signal and this will place a high voltage on the input line. A look at TI's old design in LVDS drivers has the input lines connected to the power line thro' a high resistor(300k). But the simulations work for even a low resistor(say 1k).Why is it a very high value?Am i missing something fundamental about simulation program here.
Well, simulations don't always behave like the real thing. SPICE models don't work outside their range of applicability. And simulations should never override common sense. I think all you need is common sense here.
The impedance of a typical LVDS cable/driver is 100 ohms so whether the resistor is 1K or 300K, it's a comparatively high-impedance connection to the voltage source.
What is your "high voltage"? If high voltage is greater than 5V then you will likely have degraded noise immunity/improper operation with a
1K resistor.Tim.
The high voltage is 2,5V.Thanks for the reply.
Is is possible to find a the resistance value that would give a good enough noise immunity?Cos 300K is a pretty high value and I want to know how a 100K would be any different considering 100k is still very high impedance compared to 100 ohm of a LVDS cable.
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