Equivalent Resistence

0 0 0 0 0 0 0 0 | | | | | | | | | | | | | | | | r r r r r r r r | | | | | | | | | | | | | | | | 0---r---....---r---r---r---r---r---r---....---r---r---0 | | | | | | | | r r r r r r r r | | | | | | | | . . . . . . . . . . . . . . . . | | | | | | | | r r r r r r r r | | | | | | | | 0---r---....---r---r---r---r---r---r---....---r---r---0 | | | | | | | | r r r r r r r r | | | | | | | | 0---r---....---r---r---r---r---r---r---....---r---r---0 | | | | | | | | r r r r r r r r | | | | | | | | 0---r---....---r---r-A-r-B-r---r---r---....---r---r---0 | | | | | | | | r r r r r r r r | | | | | | | | 0---r---....---r---r---r---r---r---r---....---r---r---0 | | | | | | | | r r r r r r r r | | | | | | | | 0---r---....---r---r---r---r---r---r---....---r---r---0 | | | | | | | | r r r r r r r r | | | | | | | | . . . . . . . . . . . . . . . . | | | | | | | | r r r r r r r r | | | | | | | | 0---r---....---r---r---r---r---r---r---....---r---r---0 | | | | | | | | | | | | | | | | r r r r r r r r | | | | | | | | | | | | | | | | 0 0 0 0 0 0 0 0

This is a 2D resistive grid which expands in all directions. The potential at infinite is 0 as indicated in above schematic. Find the equivalent resistence between point A and B as shown in figure above. I found out experimentally by constructing a huge grid and applying a voltage source between A and B. Then I measured the current and took ratio of voltage and current to give me equvivalent resistence. It comes out to be approximately r/2. But how can we do it analytical. does anyone have any clue how to start? Thanks.

Reply to
dhruveenews
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By inspection, it's 35 ohms.

Unless the r's are negative.

PN2222A

Reply to
PN2222A

Regardless of r, such that r>0? I don't think so.

(1/2)*r is right.

Jon

Reply to
Jonathan Kirwan

Since you have this beast, would you mind trying a few different location pairs?

if (0,0) and (1,0) gives .500 r, as you've already said, then: (0,0) and (1,1) gives .636 r 2/PI (0,0) and (2,0) gives .726 r 2-4/PI (0,0) and (2,1) gives .773 r 4/PI-1/2 (0,0) and (2,2) gives .849 r 8/(3*PI) (0,0) and (3,0) gives .861 r 17/2-24/PI (0,0) and (3,1) gives .881 r 46/(3*PI)-4 (0,0) and (3,2) gives .924 r 4/(3*PI)+1/2 (0,0) and (3,3) gives .976 r 46/(15*PI) (0,0) and (4,0) gives .954 r 40-368/(3*PI) (0,0) and (4,1) gives .965 r 80/PI-49/2 (0,0) and (4,2) gives .992 r 6-236/(15*PI) (0,0) and (4,3) gives 1.028 r 24/(5*PI)-1/2 (0,0) and (4,4) gives 1.067 r 352/(105*PI)

It should match these values, I hope!

Jon

Reply to
Jonathan Kirwan

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