I have been recently reading a great book entitled "EMC for product designers" on Google Books; after 2 days finally decided to check who the author is. :-O
A practical question: why does the book recommend putting the transient suppressors at the very beginning of the power train (fig. 14.34), without considering the exact structure of the filter? If the filter has separate differential chokes, as in the attached sim, the high transient impedance provided by the 500uH combined inductive inertia, even a 2kV surge lasting 10us happens not to be a big deal for a TVS (mere 38.5A peak).
Even if the filter does not contain a DM choke and DM filtering is based on the leakage inductance of a CMC choke, wouldn't it be beneficial to wind a tapped CMC choke and connect the mains to one end and the TVS/MOV and the CX capacitor to the tap in order to make the life of the suppresor easier?
Best regards, Piotr
Version 4 SHEET 1 1244 1520 WIRE 384 0 352 0 WIRE 512 0 464 0 WIRE 0 112 -160 112 WIRE 144 112 80 112 WIRE 288 112 224 112 WIRE 352 112 352 0 WIRE 352 112 288 112 WIRE 384 112 352 112 WIRE 512 112 512 0 WIRE 512 112 464 112 WIRE 624 112 512 112 WIRE 752 112 624 112 WIRE 880 112 752 112 WIRE 624 144 624 112 WIRE -160 160 -160 112 WIRE 752 192 752 112 WIRE 880 192 880 112 WIRE 352 208 352 112 WIRE 512 208 512 112 WIRE 624 240 624 208 WIRE 624 240 576 240 WIRE 624 272 624 240 WIRE -160 288 -160 240 WIRE 160 368 -160 368 WIRE 288 368 288 256 WIRE 288 368 240 368 WIRE 352 368 352 272 WIRE 352 368 288 368 WIRE 384 368 352 368 WIRE 512 368 512 272 WIRE 512 368 464 368 WIRE 624 368 624 336 WIRE 624 368 512 368 WIRE 752 368 752 272 WIRE 752 368 624 368 WIRE 880 368 880 272 WIRE 880 368 752 368 WIRE -160 400 -160 368 WIRE 576 400 576 240 WIRE 352 448 352 368 WIRE 384 448 352 448 WIRE 512 448 512 368 WIRE 512 448 464 448 WIRE -160 496 -160 480 WIRE 576 512 576 480 FLAG 576 512 0 FLAG -160 496 0 DATAFLAG 528 112 "" SYMBOL ind2 128 128 R270 WINDOW 0 32 56 VTop 2 WINDOW 3 5 56 VBottom 2 SYMATTR InstName L1 SYMATTR Value {Ldiff} SYMATTR Type ind SYMATTR SpiceLine Rser=100m SYMBOL ind2 144 384 R270 WINDOW 0 32 56 VTop 2 WINDOW 3 5 56 VBottom 2 SYMATTR InstName L2 SYMATTR Value {Ldiff} SYMATTR Type ind SYMATTR SpiceLine Rser=100m SYMBOL res 736 176 R0 SYMATTR InstName R1 SYMATTR Value 100 SYMBOL cap 336 208 R0 SYMATTR InstName C1 SYMATTR Value {CX} SYMBOL res 96 96 R90 WINDOW 0 0 56 VBottom 2 WINDOW 3 32 56 VTop 2 SYMATTR InstName R2 SYMATTR Value 0.2 SYMBOL cap 496 208 R0 SYMATTR InstName C2 SYMATTR Value {CX} SYMBOL ind2 368 128 R270 WINDOW 0 32 56 VTop 2 WINDOW 3 5 56 VBottom 2 SYMATTR InstName L3 SYMATTR Value {LCMC} SYMATTR Type ind SYMBOL ind2 368 384 R270 WINDOW 0 32 56 VTop 2 WINDOW 3 5 56 VBottom 2 SYMATTR InstName L4 SYMATTR Value {LCMC} SYMATTR Type ind SYMBOL cap 608 144 R0 SYMATTR InstName C3 SYMATTR Value {CY} SYMBOL cap 608 272 R0 SYMATTR InstName C4 SYMATTR Value {CY} SYMBOL res 560 384 R0 SYMATTR InstName R4 SYMATTR Value 1m SYMBOL TVSdiode 272 192 R0 WINDOW 3 -140 58 Left 2 SYMATTR Value 30KPA288CA SYMATTR InstName D1 SYMATTR Prefix X SYMBOL res 272 96 R0 SYMATTR InstName R3 SYMATTR Value 1m SYMBOL voltage -160 144 R0 WINDOW 3 -209 97 Left 2 WINDOW 123 0 0 Left 0 WINDOW 39 0 0 Left 0 SYMATTR Value SINE(0 325 50) SYMATTR InstName V2 SYMBOL voltage -160 272 R0 WINDOW 3 -315 65 Left 2 WINDOW 123 0 0 Left 0 WINDOW 39 0 0 Left 0 SYMATTR Value PULSE(0 2kV 5m 0 0 10u) SYMATTR InstName V3 SYMBOL voltage -160 384 R0 WINDOW 3 -335 74 Left 2 WINDOW 123 0 0 Left 0 WINDOW 39 0 0 Left 0 SYMATTR Value PULSE(0 200 15m 0 0 10u) SYMATTR InstName V4 SYMBOL res 480 432 R90 WINDOW 0 0 56 VBottom 2 WINDOW 3 32 56 VTop 2 SYMATTR InstName R5 SYMATTR Value 100k TEXT 80 488 Left 2 !.param LDiff=260u TEXT 80 560 Left 2 !.param LCMC=2.2m TEXT 360 536 Left 2 !K L3 L4 1 TEXT 88 624 Left 2 !.param CY=1n TEXT 88 592 Left 2 !.param CX=470n TEXT -192 720 Left 2 !.SUBCKT 30KPA288CA 1 2\n* TERMINALS: T1 T2\nDone 1 3 Dtvs\nDtwo 4 3 Dtvs\nDthr 4 5 Dtvs\nDfou 6 5 Dtvs\nDfiv 6 7 Dtvs\nDsix 8 7 Dtvs\nDsev 8 9 Dtvs\nDeig 10 9 Dtvs\nDnin 10 11 Dtvs\nDten 12 11 Dtvs\nDele 12 13 Dtvs\nDtwe 2 13 Dtvs\nRleak 1 2 288.0meg\n.MODEL Dtvs D (IS=1.0e-5 RS=0.2391 N=1.5 IBV=10m BV=54.15 CJO=4000p)\n.ENDS TEXT -496 520 Left 2 !.tran 50m