I never denied that it changes. I said that it's too complex to solve analytically, and I don't have the EM simulation software to evaluate it. My estimate is that most of the impedance change can be explained by the increased loop area, hence inductance, of the "standard" mounting method. My bottom line is the reality of the impedance difference, which I measured and posted.
All you've done, all you ever do, is whine.
John
Do you possibly think you and JF could meet somwhere away from us mere mortals and continue your absolutly OFF TOPIC discussion in private, Please :'(
-- John G.
What have you contributed to this thread?
If you don't like what we post, why are you reading our posts?
And what's OFF TOPIC about discussing the behavior of resistors in an electronics newsgroup?
John
John Larkin formulated on Monday :
Well your diatribe has nothing to do with the OP's original question.
-- John G.
--- A liar, having lied once, finds lying easier and easier with each lie and a lie, no matter how often repeated, remains a lie.
Was it once upon a time Liarkin and you decided to drop the 'i'?
-- JF
Pedantic nit to pick:
should be written as:
100 = 10 × 10^0 ohm = 10 ohms-- Paul Hovnanian mailto: snipped-for-privacy@Hovnanian.com
------------------------------------------------------------------ When I was in high school, I remember boys and girls slept together all the time. We called it algebra class. -- Jay Leno
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