Shot clock LED troubles

Hello. I've been taking care of a shot clock for a local community college, and I need some advice. The clock has 4 LEDs for each line, with two full digits (7 lines per digit). They are surface-soldered to a large, custom circuit board.

The problem I have is that the lights very often will go out halfway or completely. Since each line is in series, a single bad LED will knock out a whole line. An LED that is having trouble sometimes causes the whole line to flash or flicker.

I check the contacts and the LEDs and they are all working perfectly up until the date of use. Does anyone know why this would be? ex: I get it home, I replace any bad LEDs, and all of them work. I'll check on it periodically until it is needed for a game. The day that it is needed, LEDs go out almost immediately after it is started up.

The LEDs actually go bad. The contacts usually are not damaged enough by movement and such to cause this issue. I'll get it home the next day and I'll find LEDs on it that just don't work anymore.

Are LEDs themselves sensitive to jostling? I try not to damage them while soldering. Could it be a power cleanliness issue perhaps?

Any suggestions would be appreciated.

Thanks

Reply to
Mortrek
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I would check if the LEDs are being over-driven.

Reply to
Jumpster Jiver

The forward voltage ranges from 1.9-2.1V on the contacts, and the LEDs are rated as optimal at 2.0 to 2.5.

Reply to
Mortrek

I don't think that is what Jumpster meant. We need to know how much current is being sent through that LED. How many mA are being consumed and what is the rating for each LED. Use a simple ammeter (or milli-ammeter in series with one of the LEDs. A much better design would be to run each LED in parallel with each LED having its own current limiting resistor. This would prevent all LEDs from going out at the same time.

I guess a schematic would be nice too.

Reply to
Caesar Valenti

no schematic but basically, it's a shot clock with multiple independent LED drivers (one per "line", with 7 "lines" per digit). Each "line"/driver has a 5ohm resistor in series, along with 6 LEDs in series, and a total of 12V cumulative across the series circuit (I measured 2V per LED). I have no information on the specs/tolerances of the LEDs that came with the shot clock (the manufacturer refuses to disclose this) but my replacements are wp1503id available at mouser.com, data sheet at

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SPEC/WP1503ID.pdf I measured 45mA after opening a spot in the circuit, and since its in series that should be the same across all components in said circuit, correct?

The specs do seem to show that the standard current should be 20mA (2V-2.5V at 20mA) with an absolute max of 30, so I guess thats the culprit? Should I just boost the resistors or am I being a dumbass in that assumption? I'd love to have the whole thing be in parallel but I don't have that kind of freedom with this thing... at least not without making it into a mess...

What would be the suggestion here then?

Thanks for all the help guys :) I unfortunately have no formal electrical experience (that much should be obvious by now) and I do appreciate the help.

Reply to
Mortrek

If the LED string is being multiplex driven, then it's hard to measure the true peak current that is being driven through the LEDs. You would have to measure the current by measuring the voltage across the series limiter resistor with a 'scope, and then doing the math. That aside, if you are measuring 45mA with a DC ammeter, then it's probably at least that, which seems wildly excessive - even for the original LEDs. You are correct in that ' rule of thumb ' for years ago was 10 - 20 mA. Typically, a single panel indicator LED was driven from a convenient 12 or 15v rail, with a 1k ohm series resistor, giving a LED current of 12 or 15 mA. Modern LEDs are much more efficient than this, and my rule of thumb these days is about 5 to 10 mA for the same light output as an ' old ' type. They are still quite happy for the most part, however, with up to 20 mA.

Nothing dumbass about your suggestion of upping the resistor values - it's what the math would suggest, but I would have to question what is the cause of you having to. Just over 2v per LED is normal for a red type, so string 6 of them in series, and you need 12v or so, to run them - ergo, no series R required at all. This is a common scheme. A resistor is usually included for safety reasons, to limit the current in the event of one or multiple short circuit failures of the LEDs, or a physical short on the string. Under normal circumstances, the voltage drop across this very low value resistor -

5 ohms in your case - will be minimal, so the power dissipation in it will be low, and it will run totally cool. You could try tripling the value of the resistor to 15 ohms, and measuring again, just to see what happens. If you read a lower current, and the brightnes of the LEDs is still acceptable, then this may be enough to ' cure ' the problem, but might be doing it by masking an actual fault.

Without seeing a schematic for the whole thing, to see just how the LEDs are driven - DC, or pulsed and multiplexed - upping the resistor is about the most valid thing that I can suggest, which might result in a long term fix. It is possible that there is a genuine intermittent problem with the drive electronics, but it's curious as to just why this only seems to show when the thing is in service, rather than at your home where you are fixing it. Two things come to mind here. The first is temperature. Some intermittents are particularly temperature sensitive. The second is line supply stability, although if the thing is designed properly, it should have fully stabilized supplies, and should not care too much about line power fluctuations, provided that they are not wildly excessive.

Arfa

Reply to
Arfa Daily

Or the voltage regulator may be faulty or intermittent.

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Reply to
Sam Goldwasser

"Mortrek" wrote in news:1170923228.704325.259980 @j27g2000cwj.googlegroups.com:

If you replace one OEM LED in a string, you should probably replace the whole string because you have no idea of the ratings of the originals.

Also, you might try paralleling each LED with a fixed resistor (all the same value for that string of LEDs. You might aim for 10 ma through the resistor string, that would be 2 volts/10 ma or 44.4 ohms for each resistor. It WOULD increase the load on the LED drivers by about 11%, which might be a problem.) to 'equalize' the voltage drops across each diode in the string of LEDs.

How close to 2 volts are you getting? If, for example you have one at 2.5 and another at 1.5, differences might allow one LED to overheat and go down in resistance and efficiency, over heating more and overloading other LEDs in the same string until one or more fail.

The same 'through' each component, YES. Current goes through. Voltage is measured ACROSS.

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Reply to
bz

Why? LEDs are current driven. Their exact voltage drop is rather irrelevant as long as it isn't far off.

Sorry, if they were that different, one of the LEDs is bad. LEDs of a given color from a given manufacturer will be quite close in voltage at the same current.

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Reply to
Sam Goldwasser

Holy crap, yeah 45mA is way too much if those are ordinary LEDs. Replace the resistors with some of higher value to obtain about 18mA, if you measure the forward drop across the whole string of LEDs, you can use Ohms law to easily calculate the resistor value.

Reply to
James Sweet

Sam Goldwasser wrote in news: snipped-for-privacy@plus.seas.upenn.edu:

Agreed, As long as it isn't far off. I do know that strings of diodes often need equalizing resistors but that may be to make sure that the reverse voltage doesn't 'pile up across one diode and blow it'. I also seem to recall that there are times when zeners in series require parallel resistors.

Maybe he needs some capacitors rather than resistors. Perhaps transients are killing the LEDs. Something is.

The fact that it works fine in the shop is puzzling.

With some such problems I use a variac to run the voltage up to 125 or 130 to 'stress test' it.

No need to be sorry.

Hence my suggestion that he replace the whole string when one goes bad.

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bz

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