:) nie wiem...
Jest kilka mozliwosci dla ktorych nie beda tam dostepne sygnaly...
Moim zdaniem uklad zbyt rozbudowany - orginalna aplikacja STM jest prostsza
Jest jeden rezystor dla DAC1-3 i jeden dla DAC4-6
obecnosc 6412 komplikuje troche sprawe...
:) nie wiem...
Jest kilka mozliwosci dla ktorych nie beda tam dostepne sygnaly...
Moim zdaniem uklad zbyt rozbudowany - orginalna aplikacja STM jest prostsza
Jest jeden rezystor dla DAC1-3 i jeden dla DAC4-6
obecnosc 6412 komplikuje troche sprawe...
The resistor Rref connected to the bandgap has a direct effect on the output current which flows from the DAC outputs. For the maximum code (1023 in decimal):
Iout (max) = 80.704 / Rref
For example, with a typical value of Rref = 20 kOhms, Iout (max) = 4.04 mA for each DAC. The value of Rref must be carefully chosen: Iout must always be lower than 5 mA, otherwise, DAC linearity is not guaranteed. Because of the sensitive relationship between the DAC and Rref, the tolerance on the Rref value must be small. Typically, the Rref resistor must be a 1% resistor. The output voltage on the RGB output pins depends on the external load resistor Rload (connected between the DAC output and ground):
Vout (max) = Rload * Iout (max)
For example, with a typical load value Rload = 274 Ohms and Iout (max) =
4.04 mA, Vout (max) = 1.11 V. For any given digital input code, the output voltage of the DAC is given by the following formula:Vout = Din / 1023 * Vout (max) = (Din * Rload * 80.704) / (Rref * 1023) Vout = Din * Rload * 0.079 / Rref
For example, with Rload = 274 Ohms, Rref = 20 kOhms and Din = 526, Vout = 0.57 V
U¿ytkownik "PAndy" :
je¶li masz j± pod rêk±, to wystaw gdzie¶
tu mam parê serwisówek do tunków na 5518:
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