RLC

I'm trying to figure out how to explain it...

I think you see that in your series resonant LC the Xl and Xc cancel leaving only the R term as the impedance of the LC combination.

There is no added R to the series resonant LC so we are left with the ESR of the cap and the resistance of the coil wire. Both of these are really low so Z is consequentially low. Since the series resonant LC does not feed back to itself until the loop through the active component is complete, the current will not (can not) circulate within itself, as it is not yet a complete circuit.

This is bit like asking why glass is transparent. The best answer seems to be that there is no reason it shouldn't be.

Hi Garth

Thank you so much I learnt so much from you and other kind people up there :) So that means for parallel LC , there is a existing loop within itself. Therefore, it will keep the current in the parallel LC tank rather than let it flow to the active circuit? :) Thank you

Jason

Hi Garth

Thank you so much I learnt so much from you and other kind people up there :) So that means for parallel LC , there is a existing loop within itself. Therefore, it will keep the current in the parallel LC tank rather than let it flow to the active circuit?

For parallel LC tank, the gain of the active circuit must be greater than 1. Then the initial loop gain must be greater than

For series LC tank, what is the condition, do you know?

Thank you

Jason

Hi Garth

Thank you so much I learnt so much from you and other kind people up there :) So that means for parallel LC , there is a existing loop within itself. Therefore, it will keep the current in the parallel LC tank rather than let it flow to the active circuit?

For parallel LC tank, the gain of the active circuit must be greater than 1. Then the initial loop gain must be greater than

For series LC tank, what is the condition, do you know?

Thank you

Jason

Yes, and it will decay over time due to losses within the components.

Sorry, I don't know this one but I would guess that a gain of 2 is a practical minimum here as well.

Thank you Garth It is my honour to have learnt so much from you :) Thanks a lot and wish you good luck

rgds and thanks Jason

You're welcome Jason, I hope you continue to study and in your own time, help others as well...

Take care,

Jon

Sure Garth(or Jon). I will do my best as a learner and help people who is in need Thank you so much :)

Jason

Great, keep up with your studies! You are welcome